代码搜索：Raspberry Pi
找到约 10,000 项符合「Raspberry Pi」的源代码
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www.eeworm.com/read/334240/12615986
txt pearsonpar.txt
pi mu sigma
0.5 0.6343 0.0190
0.5 0.6551 0.0121
www.eeworm.com/read/247668/12634687
cpp p1-14.cpp
#include
const double PI=3.1416; //声明常量(const变量)PI为3.1416
main()
{
//声明3个变量
double r=3,l,s;
//计算圆的周长
l=2*PI*r;
cout
www.eeworm.com/read/247668/12634802
cpp p1-4.cpp
##include //包含iostream.h头文件
void main()
{
//输出字符常量、变量和字符串
char c1='A';
cout
www.eeworm.com/read/238364/13891591
m chap3_11f.m
function [y]=func(x1,x2,x3)
for l1=1:1:3
gs1=-[(x1+pi/6-(l1-1)*pi/6)/(pi/12)]^2;
u1(l1)=exp(gs1);
end
for l2=1:1:3
gs2=-[(x2+pi/6-(l2-1)*pi/6)/(pi/12)]^2;
u2(l2)=exp(gs2);
end
www.eeworm.com/read/300587/13904416
cpp 1010 tempter of the bone.cpp
/*
1010 Tempter of the Bone
Time Limit : 1000 ms Memory Limit : 32768 K Output Limit : 1024 K
GUN C++
*/
#include
#include
#include
using namespace std;
cons
www.eeworm.com/read/300562/13905862
m ip_07_07.m
% MATLAB script for Illustrative Problem 7, Chapter 7.
echo on
Tb=1;
f1=1000/Tb;
f2=f1+1/Tb;
phi=pi/4;
N=5000; % number of samples
t=0:Tb/(N-1):Tb;
u1=cos(2*pi*f1*t);
u2=cos(2*pi*f2*t);
% assum
www.eeworm.com/read/135728/13906287
m exa060702_2.m
%--------------------------------------------------------------------------
% exa060702_2 , for example 6.6.2 and 6.7.2;
% to test buttord.m and butter.m;
% to design a Butterworth Bandpass digital
www.eeworm.com/read/135728/13906297
m exa020502.m
%-------------------------------------------------------------------------
% exa020502.m, for example 2.5.2 and fig 2.5.6,
%------------------------------------------------------------------------
www.eeworm.com/read/135728/13906367
m exa030202.m
%----------------------------------------------------------------------------
% exa030202, for example 3.2.2 and fig 3.2.4
% to explain how to unwrap the phase
%------------------------------------
www.eeworm.com/read/238106/13906416
txt 3_1.txt
(1)
sqrt(pow(sin(x),2.5))
(2)
(a*x+(a+x)/(4*a))/2
(3)
pow(c,x*x)/sqrt(2*M_PI) //M_PI为BC中math.h中的圆周率常数