代码搜索：Raspberry Pi
找到约 10,000 项符合「Raspberry Pi」的源代码
代码结果 10,000
www.eeworm.com/read/265563/11261154
asv mimo_corr.asv
clear all
clc
Nr=4;
Nt=2;
t=10;
fig=mimo_channel(Nr, Nt,t)%;
function mimo_channel(Nr, Nt,t)
s=35;
% mm=O;
fd=5.56;
rand('state',0);
for i=1 :Nt*Nr
for l=1:1
h1=0;
www.eeworm.com/read/148391/12468645
m cell2.m
[theta,phi]=meshgrid(0:0.02*pi:2*pi,0:pi/12:1.1*pi);
the=pi/2-theta;
k=2*pi;
a=sin(the).*cos(phi);
b=sin(the).*sin(phi);
%Fac=[1,2,1;2,3,2;1,2,1];
%Fac=[0,0,0;0,1,0;0,0,0];
Fac=[1,2,1;2,-8.9849
www.eeworm.com/read/148391/12468661
m basic4.m
[theta,phi]=meshgrid(0:0.02*pi:2*pi,0:pi/12:1.1*pi);
the=pi/2-theta;
AE=platecomp(the,phi);
[x,y,z]=sph2cart(phi,theta,AE);
axis off
axis equal
[theta,phi]=meshgrid(0:0.01*pi:2*pi,0:pi/12:1.1*pi
www.eeworm.com/read/148391/12468674
m basic3.m
[theta,phi]=meshgrid(0:0.02*pi:2*pi,0:pi/12:1.1*pi);
%E=cos(theta);
the=pi/2-theta;
%phi=ones(size(phi))*pi/4;
% E=(cos(3/2*pi*cos(the)))./sin(the);
% E=cos((pi/2)*cos(the))*sin(the);
% if s
www.eeworm.com/read/148391/12468687
m basic2.m
[theta,phi]=meshgrid([0:0.02*pi:2*pi]);
%E=cos(theta);
the=pi/2-theta;
% E=(cos(3/2*pi*cos(the)))./sin(the);
% E=cos((pi/2)*cos(the))*sin(the);
k=2*pi;
x2=1/6;x1=-1/6;y2=1/6;y1=-1/6;
S=(x2-x1
www.eeworm.com/read/336138/12475118
m untitled.m
clear all;
clc;
close all;
randn('state',0);
%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%参数设置%%%%%%%%%%%%%%%%%%%%%%%%%%%%%%
Ns=512;%时域采样点数；
FF=180/180;%空域采样间隔(单位:度)
snapshots=512;
DB=-10;%信噪比；
B
www.eeworm.com/read/148257/12479708
m ag45.m
%《线性代数实验践及MATLAB入门》第四章第五节演示程序ag45
% 字符串函数库
% 电子工业出版社出版 陈怀琛 龚杰民合著 2005年10月
clear, echo on
s='abyzABYZ0189',pause
size(s),pause
abs(s),pause
setstr(abs(s)),pause
dec2hex(abs(s)),pause
s1=['
www.eeworm.com/read/148256/12480190
m q729.m
%《MATLAB及在电子信息课程中的应用》第七章例7.29程序q729
% 用脉冲响应不变法和双线性变换法将模拟滤波器离散化
% 电子工业出版社出版 陈怀琛 吴大正 高西全合著 2001年10月初版，2003年7月第二版
%
%脉冲响应不变法实现模拟到数字滤波器的转换
clear;close all
b=1000;a=[1,1000];
w=[0:1000*2*<mark>pi</mark>]; % ...
www.eeworm.com/read/335971/12486404
c 1cpdv.c
#include "math.h"
void cpdv(pr,pi,m,qr,qi,n,sr,si,k,rr,ri,l)
int m,n,k,l;
double pr[],pi[],qr[],qi[],sr[],si[],rr[],ri[];
{ int i,j,mm,ll;
double a,b,c,d,u,v;
void cmul(doubl
www.eeworm.com/read/335658/12509727
c 1cpdv.c
#include "math.h"
void cpdv(pr,pi,m,qr,qi,n,sr,si,k,rr,ri,l)
int m,n,k,l;
double pr[],pi[],qr[],qi[],sr[],si[],rr[],ri[];
{ int i,j,mm,ll;
double a,b,c,d,u,v;
void cmul(doubl