代码搜索：Raspberry Pi
找到约 10,000 项符合「Raspberry Pi」的源代码
代码结果 10,000
www.eeworm.com/read/367926/9722644
m ex5_17.m
[x,y]=meshgrid(0:0.25:4*pi);
z=sin(x+sin(y))-x/10;
mesh(x,y,z);
axis([0 4*pi 0 4*pi -2.5 1]);
www.eeworm.com/read/367926/9722662
m ex5_15.m
subplot(2,2,1);
ezplot('x^2+y^2-9');axis equal
subplot(2,2,2);
ezplot('x^3+y^3-5*x*y+1/5')
subplot(2,2,3);
ezplot('cos(tan(pi*x))',[ 0,1])
subplot(2,2,4);
ezplot('8*cos(t)','4*sqrt(2)*sin(t)',[
www.eeworm.com/read/367926/9722672
m ex5_19.m
t=0:pi/20:2*pi;
[x,y,z]= cylinder(2+sin(t),30);
subplot(2,2,1);
surf(x,y,z);
subplot(2,2,2);
[x,y,z]=sphere;
surf(x,y,z);
subplot(2,1,2);
[x,y,z]=peaks(30);
surf(x,y,z);
www.eeworm.com/read/367545/9743016
m hotqch.m
clear all
close all
a=0;b=1;m=10;T=0.5;N=1000;af=1;
f=inline('sin(pi*x)','x');
h=(b-a)/m;
k=T/N;
lmd=af^2*k/h^2; %注意lmd一定要小于0.5,只有这样差分法才稳定
x=linspace(a,b,m+1);
u(1,1:N+1)=0;
u(m+1,1:N+1)=0;
www.eeworm.com/read/367545/9743047
m cn.m
close all;
clear all;
a=0;b=1;m=10;T=0.5;N=50;af=1;
f=inline('sin(pi*x)','x');
h=(b-a)/m;
k=T/N;
lmd=af^2*k/h^2;
x=linspace(a,b,m+1);
x=x(2:m+1);
u(m)=0;
for i=1:m-1
u(i)=f(i*h);
end
www.eeworm.com/read/366932/9791567
c 1cpdv.c
#include "math.h"
void cpdv(pr,pi,m,qr,qi,n,sr,si,k,rr,ri,l)
int m,n,k,l;
double pr[],pi[],qr[],qi[],sr[],si[],rr[],ri[];
{ int i,j,mm,ll;
double a,b,c,d,u,v;
void cmul(doubl
www.eeworm.com/read/415997/11045084
m fitness.m
%适应度函数源程序（fitness.m）
function result=fitness(x,D)
sum=0;
for i=1:D
sum=sum+x(i)^2-10*cos(2*pi*x(i))+10;
end
result=sum;
www.eeworm.com/read/415746/11055999
m 4-6.m
%例程4－6 带通椭圆滤波器的幅频函数
wp1=10;
wp2=20;
Fs=100;
rp=0.5;
rs=50;
wp1=2*pi*wp1;
wp2=2*pi*wp2;
Bw=wp2-wp1;
Wo=sqrt(wp2*wp1);
[z,p,k]=ellipap(7,rp,rs);
[A,B,C,D]=zp2ss(z,p,k);
[At,Bt,Ct,Dt]=lp2b
www.eeworm.com/read/415004/11086573
m ep624.m
%《数字信号处理--原理、实现及应用》第六章 例6.1.4 设计程序：ep614.m
% 电子工业出版社出版 高西全 丁玉美 阔永红合著 2006年8月
% 椭圆滤波器设计程序
wp=2*pi*3000;ws=2*pi*12000;Rp=0.1;As=60; %设置指标参数
[N,wpo]=ellipord(wp,ws,Rp,As,'s'); %计算椭圆低通模拟滤波器阶
www.eeworm.com/read/414867/11098446
m chap3_11f.m
function [y]=func(x1,x2,x3)
for l1=1:1:3
gs1=-[(x1+pi/6-(l1-1)*pi/6)/(pi/12)]^2;
u1(l1)=exp(gs1);
end
for l2=1:1:3
gs2=-[(x2+pi/6-(l2-1)*pi/6)/(pi/12)]^2;
u2(l2)=exp(gs2);
end