代码搜索:Raspberry Pi

找到约 10,000 项符合「Raspberry Pi」的源代码

代码结果 10,000
www.eeworm.com/read/395532/8169166

m helix.m

function [fvec,J] = helix(n,m,x,opt) % ******************************************* % ******************************************* % function [ fvec, J]= helix(n,m,x,opt) % % Helical valley function [
www.eeworm.com/read/295129/8185910

m hblxjm.m

close all clear all clc f0=35000; w=2*pi*f0; fs=192000; r=0.191; d=0.225; l=7.500; c=1480.000; %------------------------------------- N=20; M=20; %=====================================
www.eeworm.com/read/294870/8196533

asv aaaaa.asv

clear clc T=128; f1=0.1; m1=0.2/T; t=1:T; s1=exp(j*2*pi.*(f1.*t+(m1/2)*t.^2)); ambifunb(s.');
www.eeworm.com/read/294870/8196782

m aaaaa.m

clear clc T=128; f1=0.1; m1=0.2/T; t=1:T; s=exp(j*2*pi.*(f1.*t+(m1/2)*t.^2)); ambifunb(s.');
www.eeworm.com/read/394604/8216756

m exm010310.m

t=0:pi/50:4*pi; y=exp(-t/3).*sin(3*t); plot(t,y,'-r','LineWidth',2) axis([0,4*pi,-1,1]) xlabel('t'),ylabel('y')
www.eeworm.com/read/394483/8221786

m test11.m

% We solve the standard wave equation % d2u/dt2-div(grad(u))=0 % on a square. % The initial conditions: % u(0)=atan(cos(pi/2*x)) and % dudt(0)=3*sin(pi*x).*ex
www.eeworm.com/read/193279/8241499

m rootmusic.m

clear all close all A=1/10; N =10; n = (-(N-1)/2:(N-1)/2)'; Vm = ones(N,1); u=1:100; SNR=10.^(20/10); ui=0.15; us=0; Vi = exp(j*n*pi*ui); Vs=exp(j*n*pi*us); Sx=zeros(10,10) for i=1:100 X
www.eeworm.com/read/193279/8241547

m music.m

clear all; close all; A=1/10; N =10; n = (-(N-1)/2:(N-1)/2)'; Vm = ones(N,1); u=1:100; SNR=10.^(20/10); ui=0.15; us=0; Vi = exp(j*n*pi*ui); Vs=exp(j*n*pi*us); Sx=zeros(10,10); for i=1:2
www.eeworm.com/read/294111/8252924

m jiaodukongzhi.m

%SHUXUE pp=load('data.txt'); nn=length(pp);m=0; d1=140;d2=255;d3=255;d4=65; for k=1:nn px=pp(k,1); py=pp(k,2); pz=pp(k,3); for s1=0:1 for s2=0:1 for s3=0:
www.eeworm.com/read/294111/8252944

m jiaodukongzhi2.m

%SHUXUE pp=load('data.txt'); nn=length(pp);m=0; d1=140;d2=255;d3=255;d4=65; for k=1:nn px=pp(k,1); py=pp(k,2); pz=pp(k,3); for s1=0:1 for s2=0:1 for s3