代码搜索：Raspberry Pi
找到约 10,000 项符合「Raspberry Pi」的源代码
代码结果 10,000
www.eeworm.com/read/212376/15157198
m exm07062_1.m
%exm07062_1.m
clc
x=pi/4;Ve=eval('1+sin(x)')
Vf=feval('1+sin(x)',x)
www.eeworm.com/read/212376/15157226
m exm060251_1.m
t=2*pi*(0:20)/20;y=cos(t).*exp(-0.4*t);
stem(t,y,'g');hold on;stairs(t,y,'r');hold off
www.eeworm.com/read/212376/15157493
m exm110633_1.m
function exm110633_1
shg;R0=1;
a=12*R0;b=9*R0;T0=2*pi;
T=5*T0;dt=pi/100;t=[0:dt:T]';
f=sqrt(a^2-b^2);
th=12.5*pi/180;
E=exp(-t/20);
x=E.*(a*cos(t)-f);
www.eeworm.com/read/212131/15165607
m parabcyl.m
function f=Parabcyl(x,r,N)
% computer parabolic cylinder funcion
% input:x,r,N
% output the value of f
%
if nargin
www.eeworm.com/read/212047/15167085
c tests.c
/* integration/tests.c
*
* Copyright (C) 1996, 1997, 1998, 1999, 2000 Brian Gough
*
* This program is free software; you can redistribute it and/or modify
* it under the terms of the GNU Genera
www.eeworm.com/read/211981/15168814
m exa060702_2.m
%--------------------------------------------------------------------------
% exa060702_2 , for example 6.6.2 and 6.7.2;
% to test buttord.m and butter.m;
% to design a Butterworth Bandpass digital
www.eeworm.com/read/211981/15168818
m exa020502.m
%-------------------------------------------------------------------------
% exa020502.m, for example 2.5.2 and fig 2.5.6,
%------------------------------------------------------------------------
www.eeworm.com/read/211981/15168844
m exa030202.m
%----------------------------------------------------------------------------
% exa030202, for example 3.2.2 and fig 3.2.4
% to explain how to unwrap the phase
%------------------------------------
www.eeworm.com/read/211606/15176715
m xggszb.m
function y=xggszb1(N)
%
%产生相关高斯杂波
%
%
%产生服从高斯分布的随机数
%
%clear;
%clc;
u1=rand(1,N); %标准正态分布的随机数
u2=rand(1,N); %
for i=1:N
x(i)=sqrt((-2)*log2(u1(i)))*cos(2*pi*u2(i));
end
%
%求滤波
www.eeworm.com/read/211606/15176716
m xggszb1.m
function y=xggszb(N)
%
%产生相关高斯杂波
%
%
%产生服从高斯分布的随机数
%
clear;
clc;
u1=rand(1,N); %标准正态分布的随机数
u2=rand(1,N); %
for i=1:N
x(i)=sqrt((-2)*log2(u1(i)))*cos(2*pi*u2(i));
end
%
%求滤波器系数