代码搜索：Raspberry Pi
找到约 10,000 项符合「Raspberry Pi」的源代码
代码结果 10,000
www.eeworm.com/read/346860/11718220
m ex5_19.m
t=0:pi/20:2*pi;
[x,y,z]= cylinder(2+sin(t),30);
subplot(2,2,1);
surf(x,y,z);
subplot(2,2,2);
[x,y,z]=sphere;
surf(x,y,z);
subplot(2,1,2);
[x,y,z]=peaks(30);
surf(x,y,z);
www.eeworm.com/read/157294/11721329
m exa060702_2.m
%--------------------------------------------------------------------------
% exa060702_2 , for example 6.6.2 and 6.7.2;
% to test buttord.m and butter.m;
% to design a Butterworth Bandpass digital
www.eeworm.com/read/346772/11723683
m 求如下三个系统的幅频响应.m
%-------------------------------------------------------------------------
% exa020502.m, for example 2.5.2 and fig 2.5.6,
%------------------------------------------------------------------------
www.eeworm.com/read/346772/11723718
m explain how to unwrap the phase.m
%----------------------------------------------------------------------------
% exa030202, for example 3.2.2 and fig 3.2.4
% to explain how to unwrap the phase
%------------------------------------
www.eeworm.com/read/346772/11723737
m 设计 butterworth 带通滤波器.m
%--------------------------------------------------------------------------
% exa060702_2 , for example 6.6.2 and 6.7.2;
% to test buttord.m and butter.m;
% to design a Butterworth Bandpass digital
www.eeworm.com/read/156813/11762241
cpp p1-14.cpp
#include
const double PI=3.1416; //声明常量(const变量)PI为3.1416
main()
{
//声明3个变量
double r=3,l,s;
//计算圆的周长
l=2*PI*r;
cout
www.eeworm.com/read/156813/11762330
cpp p1-4.cpp
##include //包含iostream.h头文件
void main()
{
//输出字符常量、变量和字符串
char c1='A';
cout
www.eeworm.com/read/346192/11763050
m filter.m
PI=3.14159;
%=====%part1%=========%原始信号的产生%======%
%y=sin（wx），其中：w=2∏/T=2∏f
%对于模拟频率，需要对其采样，根据采样点数N与采样频率fs决定，y（k）=sin（wx*k/fs）,等于是将原来的信号1s采样2000个，而采样频率为
%4000hz，等于说每2hz采一个信号
%============copyright
www.eeworm.com/read/156653/11786278
m ex031200.m
n = -5:10; x = sin(pi*n/2);
k = -100:100; w = (pi/100)*k; % frequency between -pi and +pi
X = x * (exp(-j*pi/100)).^(n'*k); % DTFT of x
% signal decomposition
[xe,xo,m] = evenodd(x,n);
www.eeworm.com/read/156528/11794973
m new_neg.m
function [y,PI] = new_neg()
%
%A new On-Line Negentropy-based Algorithm for Blind Source Separation
%copyright 2005.4.14
%author:lucky zhang
%used to separate audio signal
%usage:[y,PI]=based_ne