代码搜索:Raspberry Pi

找到约 10,000 项符合「Raspberry Pi」的源代码

代码结果 10,000
www.eeworm.com/read/332124/12777514

c 矩阵转换.c

void trans(int *p,int n) { int i,j,temp; int *pi,*pj; for(i=0;i
www.eeworm.com/read/144351/12801174

m q729.m

%《MATLAB在电子信息课程中的应用》第七章例7.29程序q729 % 用脉冲响应不变法和双线性变换法将模拟滤波器离散化 % 电子工业出版社出版 陈怀琛 吴大正 高西全合著 2001年10月 %脉冲响应不变法实现模拟到数字滤波器的转换 clear;close all b=1000;a=[1,1000]; w=[0:1000*2*pi]; % 设定模拟频率 [hf,w]
www.eeworm.com/read/331806/12807294

m dfs.m

function [Xk]=dfs(xn,N) n=[0:1:(N-1)]; k=[0:1:N-1]; WN=exp(-j*2*pi/N); nk=n'*k; WNnk=WN.^nk; Xk=xn*WNnk;
www.eeworm.com/read/331559/12821336

m chap4_9s.m

function [sys,x0,str,ts] = spacemodel(t,x,u,flag) switch flag, case 0, [sys,x0,str,ts]=mdlInitializeSizes; case 1, sys=mdlDerivatives(t,x,u); case 3, sys=mdlOutputs(t,x,u); case
www.eeworm.com/read/331559/12821360

m chap4_7s.m

function [sys,x0,str,ts] = spacemodel(t,x,u,flag) switch flag, case 0, [sys,x0,str,ts]=mdlInitializeSizes; case 1, sys=mdlDerivatives(t,x,u); case 3, sys=mdlOutputs(t,x,u); case
www.eeworm.com/read/245000/12826678

cpp 主函数.cpp

//计算素数 #include "stdafx.h" #include "stdio.h" #include "stdlib.h" #include "time.h" #include "math.h" typedef __int64 bint; void GetMiu(int *PList ,int *Miu, int a,int x_13);
www.eeworm.com/read/245000/12826730

cpp 主函数.cpp

// 计算pi(x)伪代码.cpp : Defines the entry point for the console application. // #include "stdafx.h" #include "stdio.h" #include "math.h" #include "s2.h" int main(int argc, char* argv[]) {
www.eeworm.com/read/244937/12831093

m ip_07_07.m

% MATLAB script for Illustrative Problem 7.7. clear echo on Tb=1; f1=1000/Tb; f2=f1+1/Tb; phi=pi/4; N=5000; % number of samples t=0:Tb/(N-1):Tb; u1=cos(2*pi*f1*t); u2=cos(2*pi*f2*t);
www.eeworm.com/read/143830/12837949

m 9fen.m

clf,b=2*pi;x=linspace(0,b,50); for k=1:9 y=sin(k*x); subplot(3,3,k),plot(x,y),axis([0 2*pi -1 1]) end
www.eeworm.com/read/244597/12853260

cpp xmoment.cpp

#include #include #include #include "nr.h" using namespace std; // Driver for routine moment int main(void) { const int NPTS=5000,NBIN=100,NPPNB=NPTS+N