代码搜索:Raspberry Pi

找到约 10,000 项符合「Raspberry Pi」的源代码

代码结果 10,000
www.eeworm.com/read/198282/7942265

m examp8_19.m

maple('with(numtheory):'); f=maple(['cfe:=cfrac(pi,20)']) n=maple('nthnumer','cfe',4); d=maple('nthdenom','cfe',4); [vpa(n),vpa(d)]
www.eeworm.com/read/198282/7942608

m examp3_33.m

f=inline('cos(15*x)','x'); tic, S=quadl(f,0,3*pi/2,1e-15), toc S1=quad(f,0,3*pi/2) % 采用默认精度 S1=quad(f,0,3*pi/2,1e-15)
www.eeworm.com/read/198282/7942904

m examp5_13.m

syms t k; syms a positive f1=t; f2=a-t; Fs=int(f1*sin(k*pi*t/a),t,0,a/2)+int(f2*sin(k*pi*t/a),t,a/2,a); simple(Fs)
www.eeworm.com/read/198282/7943002

m examp10_19.m

syms t; f=(1-t^2)*exp(-t^2/2)/sqrt(2*pi); ezplot(f,-4,4), hold on; % 绘制基小波,并保护坐标系不被刷新 ezplot(subs(f,t,t-1),-4,4); ezplot(subs(f,t,t+1),-4,4) % 小波平移 figure; ezplot(f,-4,4), hold on; ezplot(subs(f
www.eeworm.com/read/298271/7969395

asv untitled5.asv

%用公式法实现圆阵指向性图的绘制 close all clear all; N=28;M=60; c=1500; f=1500; fs=5000; lamda=c/f; r=lamda/0.4; jiajiao=2*pi/N; nfft=256; d=0.5; n=1:nfft; alpha=0.5; derta2=0; f0=5000; A=2
www.eeworm.com/read/298099/7974439

m ex0408.m

%用不同线段类型、颜色和数据点形画曲线 x=0:0.1:2*pi; plot(x,sin(x),'r-.') %用红色点划线画出曲线 hold on plot(x,cos(x),'b:o') %用蓝色圆圈画出曲线,用点线连接
www.eeworm.com/read/197671/7979711

c 1cpdv.c

#include "math.h" void cpdv(pr,pi,m,qr,qi,n,sr,si,k,rr,ri,l) int m,n,k,l; double pr[],pi[],qr[],qi[],sr[],si[],rr[],ri[]; { int i,j,mm,ll; double a,b,c,d,u,v; void cmul(doubl
www.eeworm.com/read/197646/7983403

m exp2_4_.m

close all clc clear %定义时间范围 t=[0:pi/20:9*pi]; hold on %允许在同一坐标系下绘制不同的图形 plot(t,sin(t),'r:*') plot(t,cos(t)) plot(t,-cos(t),'k') grid on %在所画出的图形坐标中添加栅格,注意用在plot之后 hold off %覆盖旧图
www.eeworm.com/read/197646/7983417

m exp2_4.m

close all clc clear %定义时间范围 t=[0:pi/20:9*pi]; figure(1) %选择图像 plot(t,sin(t),'r:*') grid on %在所画出的图形坐标中添加栅格,注意用在plot之后 grid off %删除栅格 figure(2) plot(t,cos(t)) grid on grid off
www.eeworm.com/read/197261/8008838

m cc64.m

% Matlab code to produce the 0 phase version of % length 8 complementary code set % Set up data bits matrix db=zeros(64,6); db(2,6)=1; for i=1:2 db(i+2,6)=db(i,6); db(i+2,5)=1; end fo