代码搜索:Raspberry Pi

找到约 10,000 项符合「Raspberry Pi」的源代码

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www.eeworm.com/read/439446/7708704

m p3_1.m

% Program P3_1 % Evaluation of the DTFT clf; % Compute the frequency samples of the DTFT w = -4*pi:8*pi/511:4*pi; num = [2 1];den = [1 -0.6]; h = freqz(num, den, w); % Plot the DTFT subplot(2,1,1) pl
www.eeworm.com/read/439271/7713468

m chap4_9ctrl.m

function [sys,x0,str,ts] = MIMO_Tong_s(t,x,u,flag) switch flag, case 0, [sys,x0,str,ts]=mdlInitializeSizes; case 1, sys=mdlDerivatives(t,x,u); case 3, sys=mdlOutputs(t,x,u); case {
www.eeworm.com/read/439271/7713610

m chap5_10.m

%Iterative learning control for mobile robot path-tracking clear all; close all; ts=0.001; %Sample time for k=1:1:2001 xd(k)=cos((k-1)*pi*ts); yd(k)=sin((k-1)*pi*ts
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m exa060702_2.m

%-------------------------------------------------------------------------- % exa060702_2 , for example 6.6.2 and 6.7.2; % to test buttord.m and butter.m; % to design a Butterworth Bandpass digital
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m exa020502.m

%------------------------------------------------------------------------- % exa020502.m, for example 2.5.2 and fig 2.5.6, %------------------------------------------------------------------------
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m exa030202.m

%---------------------------------------------------------------------------- % exa030202, for example 3.2.2 and fig 3.2.4 % to explain how to unwrap the phase %------------------------------------
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c 1cpdv.c

#include "math.h" void cpdv(pr,pi,m,qr,qi,n,sr,si,k,rr,ri,l) int m,n,k,l; double pr[],pi[],qr[],qi[],sr[],si[],rr[],ri[]; { int i,j,mm,ll; double a,b,c,d,u,v; void cmul(doubl
www.eeworm.com/read/438661/7728583

m squareroot.m

function z=squareroot(T,alpha,x) t=-5.*T; for i=1:101 t=t+0.1.*T; if t==0 y(i)=1; else y(i)=4.*alpha.*(cos((1+alpha).*pi.*t./T)+sin((1-alpha).
www.eeworm.com/read/438661/7728617

m rsquareroot.m

function z=rsquareroot(T,alpha) t=-5.*T:0.1.*T:5.*T; y=4.*alpha.*(cos((1+alpha).*pi.*t./T)+sin((1-alpha).*pi.*t./T)./(4.*alpha.*t./T))./(pi.*square(T).*(1-(4.*alpha.*t./T).^2)); x=
www.eeworm.com/read/438661/7728618

m xrc.m

function [y]=xrc(f,alpha,t) if(abs(f)>((1+alpha)/(2*t))), y=0; elseif(abs(f)>((1-alpha)/(2*t))), y=(t/2)*(1+cos((pi*t/alpha)*(abs(f)-(1-alpha)/(2*t)))); else y=t; end;