代码搜索：Raspberry Pi
找到约 10,000 项符合「Raspberry Pi」的源代码
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www.eeworm.com/read/441886/7663255
m exa030202.m
%----------------------------------------------------------------------------
% exa030202, for example 3.2.2 and fig 3.2.4
% to explain how to unwrap the phase
%------------------------------------
www.eeworm.com/read/441884/7663267
m exa030202.m
%----------------------------------------------------------------------------
% exa030202, for example 3.2.2 and fig 3.2.4
% to explain how to unwrap the phase
%------------------------------------
www.eeworm.com/read/441883/7663273
m exa020502.m
%-------------------------------------------------------------------------
% exa020502.m, for example 2.5.2 and fig 2.5.6,
%------------------------------------------------------------------------
www.eeworm.com/read/441880/7663295
m exa020502.m
%-------------------------------------------------------------------------
% exa020502.m, for example 2.5.2 and fig 2.5.6,
%------------------------------------------------------------------------
www.eeworm.com/read/441764/7665671
m cronig.m
clear all;
clc;
global P;
global Rg;
global a;
global abg;
P = 13.1;
Rg = 5.76; % meV
a = 10; % nm
abg = 9.97; % nm
N = 2000;
x = [-pi : 2*pi/(N-1) : pi];
y = [0.001 : (5*pi - 0.001)/(N-1) :
www.eeworm.com/read/440896/7679058
m p2_1.m
% Program P2_1
% Evaluation of the DTFT
close all ; clear all;
% Compute the frequency samples of the DTFT
w = -4*pi:8*pi/511:4*pi;
num = [2 1];den = [1 -0.6];
h = freqz(num, den, w);
% Plot t
www.eeworm.com/read/440896/7679060
m p2_a3.m
% Program P2_A3
% Evaluation of the DTFT
close all ; clear all;
% Compute the frequency samples of the DTFT
w = -4*pi:8*pi/511:4*pi;
num = [0.7 -0.5 0.3 1];den = [1 -0.3 -0.5 0.7];
h = freqz(nu
www.eeworm.com/read/440896/7679069
m p2_a4.m
% Program P2_A4
% Evaluation of the DTFT
close all ; clear all;
% Compute the frequency samples of the DTFT
w = -4*pi:8*pi/511:4*pi;
num = [1 3 5 7 9 11 13 15 17];
h = freqz(num, 1, w);
% Plot
www.eeworm.com/read/439850/7700819
m chap3_11f.m
function [y]=func(x1,x2,x3)
for l1=1:1:3
gs1=-[(x1+pi/6-(l1-1)*pi/6)/(pi/12)]^2;
u1(l1)=exp(gs1);
end
for l2=1:1:3
gs2=-[(x2+pi/6-(l2-1)*pi/6)/(pi/12)]^2;
u2(l2)=exp(gs2);
end
www.eeworm.com/read/439811/7701512
m ip_07_07.m
% MATLAB script for Illustrative Problem 7.7.
clear
echo on
Tb=1;
f1=1000/Tb;
f2=f1+1/Tb;
phi=pi/4;
N=5000; % number of samples
t=0:Tb/(N-1):Tb;
u1=cos(2*pi*f1*t);
u2=cos(2*pi*f2*t);