代码搜索:Raspberry Pi

找到约 10,000 项符合「Raspberry Pi」的源代码

代码结果 10,000
www.eeworm.com/read/357617/10204770

txt 08-26.txt

>> syms x y >> f = y/(1 + x^2 + y^2); >> subplot(1,2,1),ezmeshc(f,[-5,5,-2*pi,2*pi],30),title('mesh'); >> subplot(1,2,2),ezsurfc(f,[-5,5,-2*pi,2*pi],30),title('surf');
www.eeworm.com/read/357617/10204797

txt 08-45.txt

>> F =pi^(1/2)*exp(-1/4*w^2); >> ifourier(F) >> G =2/(1+t^2); >> ifourier(G) >> simplify(G) >> clear >> syms x real >> g = exp(-abs(x)); >> ifourier(g) >> clear >> syms w
www.eeworm.com/read/357506/10208335

m program_3_2.m

% Program 3_2 % Generate the filter coefficients h1 = ones(1,5)/5; h2 = ones(1,14)/14; % Compute the frequency responses [H1,w] = freqz(h1, 1, 256); [H2,w] = freqz(h2, 1, 256); % Compute and p
www.eeworm.com/read/162982/10254343

m bendcoeff.m

function c=bendcoeff(rom,ros,D,lamda) c=(rom-ros)/(rom-ros+D/9*(2*pi/lamda)^4);
www.eeworm.com/read/281237/10255010

m fir.m

%由模拟滤波器指标求理想低通数字滤波器的参数 clear wp=0.2*pi; %wp为通带截止频率 ws=0.4*pi; %ws为阻带下限频率 A=-40; %A为最大边瓣峰值 %首先得角频率 %归一化过渡带 b=ws-wp; k=1; %根据最小阻带衰减来确定窗函数类型 if A
www.eeworm.com/read/355530/10258987

m exp2_4_.m

close all clc clear %定义时间范围 t=[0:pi/20:9*pi]; hold on %允许在同一坐标系下绘制不同的图形 plot(t,sin(t),'r:*') plot(t,cos(t)) plot(t,-cos(t),'k') grid on %在所画出的图形坐标中添加栅格,注意用在plot之后 hold off %覆盖旧图
www.eeworm.com/read/355530/10259005

m exp2_4.m

close all clc clear %定义时间范围 t=[0:pi/20:9*pi]; figure(1) %选择图像 plot(t,sin(t),'r:*') grid on %在所画出的图形坐标中添加栅格,注意用在plot之后 grid off %删除栅格 figure(2) plot(t,cos(t)) grid on grid off
www.eeworm.com/read/355387/10271751

m xianmusic.m

clc clear for i=1:10; sm=6; %阵元数 snr=10; %信噪比dB nd=120; %快拍数 snr=10.^(snr/20); %信噪比 f=4*10^3*
www.eeworm.com/read/355385/10271775

m yuanmusic.m

%%%6 sensor. 4-8GHz%%% clc clear tic ccc1=cputime; sm=7;%阵元数 snr=20; nd=100;%快拍数 md=181; %? snr=10.^(snr/20); f=4*10^3*10^6; wl=3*10^8/f; r=wl/2 diz=[0 0 0
www.eeworm.com/read/280878/10283163

c 1cpdv.c

#include "math.h" void cpdv(pr,pi,m,qr,qi,n,sr,si,k,rr,ri,l) int m,n,k,l; double pr[],pi[],qr[],qi[],sr[],si[],rr[],ri[]; { int i,j,mm,ll; double a,b,c,d,u,v; void cmul(doubl