代码搜索：Raspberry Pi
找到约 10,000 项符合「Raspberry Pi」的源代码
代码结果 10,000
www.eeworm.com/read/160151/10564130
c fft2.c
#include
/*pr：输入实部
pi：输入虚部
n为2^k，n不小于数据个数
l：为0表示正变换，1表示反变换
il：1表示fr为取模结果。0表示fr输出实部fi输出虚部
*/
void FFT(double* pr, double* pi, int n, int k, double* fr, double* fi, int l, int il)
{
i
www.eeworm.com/read/159906/10591382
m 3-12.m
plot(0:pi/20:2*pi,sin(0:pi/20:2*pi))
text(pi,0,' \leftarrow sin(\pi)','FontSize',18)
www.eeworm.com/read/351894/10599590
m dtmf.m
f = [697 770 852 941 1209 1336 1477 1633];
coef = [27980 26956 25701 24219 19073 16325 13085 9315];
fs = 8000;
N = 125;
k = 8;
lf = 1;
hf = 8;
is = cos(0 : (2*pi*f(lf))/fs : (2*N*pi*f(lf))/fs)
www.eeworm.com/read/350382/10746107
m 3-6.m
%例程3-6 产生Dirichlet函数波形
t=[-4*pi:0.1:4*pi];
x=diric(t,7);
y=diric(t,6);
subplot(2,1,1);
plot(t,x);
subplot(2,1,2);
plot(t,y);
www.eeworm.com/read/276136/10762366
java planecrash.java
public class planecrash
{ public static void main(String[] args)
{ boolean [][] number=new boolean[6][6];
double x[]={0,150,85,150,145,130};
double y[]={0,140,85,155,50,150};
double
www.eeworm.com/read/274718/10857255
cpp 6_46.cpp
#include
using namespace std;
int main()
{ int *pi;
//pi=3.5;//语句1：错误，没有内存单元被分配给*pi
int i=3;
pi=&i;//语句2：通过将变量的地址赋给指针变量进行初始化
cout
www.eeworm.com/read/418911/10891962
m shaw.m
function [A,b,x] = shaw(n)
%SHAW Test problem: one-dimensional image restoration model.
%
% [A,b,x] = shaw(n)
%
% Discretization of a first kind Fredholm integral equation with
% [-pi/2,pi/2] as both
www.eeworm.com/read/273787/10901148
m bio1.m
% A New Class of Two-Channel Biorthogonal Filter Banks and Wavelet Bases
% H is the magnitude square, integral sum is objective function
% 0.6*pi is stopband edge, 0.4*pi is passband edge.
H = '
www.eeworm.com/read/273606/10908682
m ex5_4.m
x=0:pi/100:2*pi;
y1=0.2*exp(-0.5*x).*cos(4*pi*x);
y2=2*exp(-0.5*x).*cos(pi*x);
plotyy(x,y1,x,y2);