代码搜索:Probability

找到约 4,670 项符合「Probability」的源代码

代码结果 4,670
www.eeworm.com/read/143453/12874757

m nu_rbfsvc_train.m

function [output]=nu_RbfSVC_Train(data, savefile, C, gamma, nu, options) %options: options.crossvalidation=0 if crossvalidation is not needed. % otherwise, options.crossvalidation=v(v>=2) fo
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m polysvc_train.m

function [output]=PolySVC_Train(data, savefile, C, gamma, degree, coef0, options) %options: options.crossvalidation=0 if crossvalidation is not needed. % otherwise, options.crossvalidation=v
www.eeworm.com/read/244076/12891964

m crover.m

function [out1,out2]=crover(in1,in2,pcross) % % [out1,out2]=crover(in1,in2,pcross); % % Crosses two input members with a probability % of crossover of pcross (
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apb simple3a.apb

program simple3a; { simple3a: a program to flip 20 coins and keep track of heads and tails uses repeat-until construct } const ncoins = 20; { numb
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apb simple3b.apb

program simple3b; { simple3b: a program to flip 20 coins and keep track of heads and tails uses while-do construct } const ncoins = 20; { numb
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apb simple3.apb

program simple3; { simple3: a program to flip 20 coins and keep track of heads and tails } { use for-do construct } const ncoins = 20; { numbe
www.eeworm.com/read/243505/12936851

m range_func.m

function pr = slam_rfunc(x, bpos, range, sigma) % distance of this particle from the beacon d = x - ones(numrows(x),1)*bpos'; r = sqrt( sum(d'.^2) )'; % the ranges from each particle to the be
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m caltable.m

% calculate probability of a specific value i=0; for x1=0:0.1:1 i=i+1; ei=2.7183; e1=ei^(-x1^2.0/2); s1=1.0/sqrt(2*pi); % cdf b(i,1)=normcdf(x1,0,1); % pdf b(i,2)=s1*e1; % 1th b(i,
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m ncalcdf.m

function cdfi=NCalCdf(x, mui, smgi, U3i, U4i, U5i) % calculate probability of a specific value % using Edgeworth's series x1=(x-mui)/smgi; ei=2.7183; e1=ei^(-x1^2.0/2); s1=1.0/sqrt(2*pi);
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m calpdf.m

function pp=CalPdf(x, mui, smgi, c3i, c4i, c5i, c6i, c7i, c8i, c9i) % calculate probability of a specific value x1=(x-mui)/smgi; ei=2.7183; e1=ei^(-x1^2.0/2); s1=1.0/sqrt(2*pi); % cdf b0=no