代码搜索结果

#include #include int grid[6][7]; int op[6][7]; int a[6][7]; int out[6][7]; void next() { int j; for(j=5;j>=0;j--) { if(j==5) op[0][j]++;

#include #include #include using namespace std; #include "OperClient.h" int main() { OperClient op; char ch; cout

% Figure 15.6 A backward chaining interpreter for if-then rules. % A simple backward chaining rule interpreter :- op( 800, fx, if). :- op( 700, xfx, then). :- op( 300, xfy, or). :- o

%99年中国大学生数学建模竞赛a题：自动化车床管理模型一 %参见《数学的实践与认识》2000.1.p36-40 clear;opt=inf; for n=[10 20 30] for m=[200 300 400] [x0,op]=fmins('jm99afun',[n m]); if op(8)

function [x,opt]=jm99a(n,m) %99年中国大学生数学建模竞赛a题：自动化车床问 %参见《数学的实践与认识》2000.1.p36-40 opt=inf; for n=10:5:30 for m=300:10:400 [x0,op]=fmins('jm99afun',[n m]); if op(8)

#include void main(void) { double x,y,result; char op; int flag; printf("input x,y,op:\n"); scanf("%lf%lf%c",&x,&y,&op); flag=1; switch(op) { case '+': result=x+y;

//switch01.cpp #include //cout #include //getch() void main() { short a,b; char op; cout > a >> b; do { cout

//EX07-04.cpp #include //cout,cin #include // getch() float operation(char,float,float); void main() { float a,b; char op,yn; cout >a>>b; do { co

//ex01-07.cpp #include #include void main() { float R=30, Volt=220, amp; amp = Volt / R; cout