代码搜索:Num

找到约 10,000 项符合「Num」的源代码

代码结果 10,000
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cpp ysf.cpp

#include #include typedef struct node { int num; int password; struct node *next; }node, *LinkList; InitList(node *p) { p=(node *)malloc(sizeof(node)); p->ne
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m frame_syn.m

len=100; %每帧的数据长度 n=3; %进行仿真的帧数 c=[1 1 1 -1 -1 1 -1]; %巴克码 for i=1:n s(i,:)=randsrc(1,len); %产生每周的信源数据 end r=[c s(1,:) c s(2,:) c s(3,:)]; %将巴克码插入信源数据中 thr=6; %判决门限,
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cpp soj2984fibonacci矩阵分治.cpp

#include #include const int MAX = 2
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cpp soj2993nim变形.cpp

#include int main(void) { int num[1000]; int n; while(scanf("%d",&n)&&n) { int i; for(i=0;i
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cpp soj2704快速分解组合数.cpp

#include #include const int MAX = 1000001; int a[MAX]; int next(int i) { int j=i+1; while(a[j]==1&&j
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cpp soj2427floyed算法.cpp

#include #define NIL 99999999 int main(void) { int n,m; while(scanf("%d%d",&n,&m)==2&&(n||m)) { int num[101][101]={0}; int i; for(i=1;i
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cpp soj3020多重集的排列问题.cpp

#include #include const int MAX = 2
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txt 1.txt

import java.awt.*; import java.awt.event.*; import javax.swing.*; import java.io.*; import java.util.*; public class Lei { public static void main(String args[]) { new ManagerWindow(
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txt 分数.txt

struct frac{ int num,den; }; double fabs(double x){ return x>0?x:-x; } int gcd(int a,int b){ int t; if (a
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txt 置换(polya).txt

//求置换的循环节,polya原理 //perm[0..n-1]为0..n-1的一个置换(排列) //返回置换最小周期,num返回循环节个数 #define MAXN 1000 int gcd(int a,int b){ return b?gcd(b,a%b):a; } int polya(int* perm,int n,int& num){ int i,j,p,v[M