代码搜索：Num
找到约 10,000 项符合「Num」的源代码
代码结果 10,000
www.eeworm.com/read/423867/10528744
java client_get.java
/**
*协议的Client_Get状态.
*/
import java.util.Timer;
import java.io.FileInputStream;
public class Client_Get extends State {
public static FileIOClass myfile;//将要存储的文件名
public static ComCla
www.eeworm.com/read/423867/10528855
java server_start.java
/**
*协议的服务器端启动状态.
*是Server_State状态的下一个状态
*执行它的doIt方法,并转入下一个状态
*/
import java.io.IOException;
import java.util.Timer;
public class Server_Start extends State {
public static FileIOClass
www.eeworm.com/read/352590/10534231
bas module1.bas
Attribute VB_Name = "Module1"
Declare Function GetAsyncKeyState Lib "user32" (ByVal vKey As Long) As Integer
Declare Function GetMessageTime Lib "user32" () As Long
Public X1, X2, X3, X4, Y1, Y2, Y
www.eeworm.com/read/160306/10544300
cpp evaluation.cpp
// Evaluation.cpp: implementation of the CEvaluation class.
//
//////////////////////////////////////////////////////////////////////
#include "Evaluation.h"
#include
/////////////
www.eeworm.com/read/423580/10545435
m txttomt01.m
function mtdata=txttomt01(filename,num)
%TXTTOMT 文本转矩阵
for i=1:num
mtdata(1,i)=i;
end
fid=fopen(filename,'rt');
if fid == -1
('Error opening the file')
end
k=1;
while 1
k=k+1;
www.eeworm.com/read/160253/10548847
m example6_1.m
%首先装载一原始信号
load nearbrk;
s=nearbrk;
%===========================
%画出该信号的波形图
subplot(4,2,1);
plot(s);
Ylabel('s');
title('原始信号s和信号的近似a、细节d');
%===========================
%用小波
www.eeworm.com/read/278099/10569694
c etphi.c
/* +++Date last modified: 05-Jul-1997 */
/*
** ETPHI.c
**
** Compute Euler's Totient function, phi().
** phi(n) = the number of positive integers less than n
** which have no common factor
www.eeworm.com/read/423266/10574939
m m7_9.m
%Expert PID Controller
clear all;
close all;
ts=0.001;
sys=tf(5.235e005,[1,87.35,1.047e004,0]);
dsys=c2d(sys,ts,'z');
[num,den]=tfdata(dsys,'v');
u_1=0.0;u_2=0.0;u_3=0.0;
y_1=0;y_2=0;y_3=0
www.eeworm.com/read/423266/10574974
m m5_19.m
A=[0 1 0 0;0 0 1 0;0 0 0 1;-50 -48 -28.5 -9];
B=[0;0;0;1];
C=[10 2 0 0];
D=0;
[num,den]=ss2tf(A,B,C,D)
G=tf(num,den)
www.eeworm.com/read/423266/10574990
m m5_13.m
%1
num=[2 18 40];
den=[1 6 11 6];
G=tf(num,den);
Gs=ss(G)
%2
num=[2 18 40];
den=[1 6 11 6];
[A,B,C,D]=tf2ss(num,den)