代码搜索：Num
找到约 10,000 项符合「Num」的源代码
代码结果 10,000
www.eeworm.com/read/279355/10445557
c 15ikey0.c
#define HEAPSORT struct student
#define KEY age
HEAPSORT
{ int num;
char name[8];
char sex;
int age;
double score;
};
#include "stdio.h"
#include
www.eeworm.com/read/161132/10446699
c lru1.c
#include
#include
typedef struct lru
{
int num;
int time;
}Lru;
Lru b[5];
int c[5][10];
int queue[100];
int K;
void Init(Lru *b,int c[5][10])
{
int
www.eeworm.com/read/279286/10447986
pas unit2.pas
////////////////////////////////////////////////////////////////////////////////
//题目：假设有一种细胞，从出生后第三秒起每秒（发育成熟了）都产生了一个新细胞，//
//后代细胞长到第三秒后也一样，每秒又分裂了一只细胞，假设所有细胞的寿命固定为 //
//10秒，且第9,10秒属于老年期细胞不再分裂，问从第1
www.eeworm.com/read/279286/10448002
~pas unit2.~pas
////////////////////////////////////////////////////////////////////////////////
//题目：假设有一种细胞，从出生后第三秒起每秒（发育成熟了）都产生了一个新细胞，//
//后代细胞长到第三秒后也一样，每秒又分裂了一只细胞，假设所有细胞的寿命固定为 //
//10秒，且第9,10秒属于老年期细胞不再分裂，问从第1
www.eeworm.com/read/279224/10454305
js datatrans.js
// some methods about the data ,eg. json , xml
/*
* @author: shennan , amushen@yahoo.com.cn
*/
function numToType(num){
//节点类型的转换，将数字转成对应的字符串
num=parseInt(num);
switch(num){
case 1:
www.eeworm.com/read/160929/10469390
m p7_1.m
% Program P7_1
% Design of a Butterworth Bandstop Digital Filter
Ws = [0.4 0.6]; Wp = [0.2 0.8]; Rp = 0.4; Rs = 50;
% Estimate the Filter Order
[N1, Wn1] = buttord(Wp, Ws, Rp, Rs);
% Design the Filte
www.eeworm.com/read/160929/10469408
m p6_2.m
% Program P6_2
% Parallel Form Realizations of an IIR Transfer
num = input('Numerator coefficient vector = ');
den = input('Denominator coefficient vector = ');
[r1,p1,k1] = residuez(num,den);
[r2,p
www.eeworm.com/read/160929/10469531
m noisepwr2.m
function nvar = noisepwr2(num,den)
% Computes the approximate output noise variance due
% to input quantization of a digital filter
% by summing the square of the impulse response samples
%
% num and
www.eeworm.com/read/160929/10469561
m noisepwr1.m
function nvar = noisepwr1(num,den)
% Computes the output noise variance due
% to input quantization of a digital filter
% based on a partial-fraction approach
%
% num and den are the numerator and den
www.eeworm.com/read/160929/10469625
m p2_5.m
% Program P2_5
% Compute the impulse response y
clf;
N = 40;
num = [2.2403 2.4908 2.2403];
den = [1 -0.4 0.75];
y = impz(num,den,N);
% Plot the impulse response
stem(y);
xlabel('Time index n'); ylabel