代码搜索：Num
找到约 10,000 项符合「Num」的源代码
代码结果 10,000
www.eeworm.com/read/181568/9245737
bas module1.bas
Attribute VB_Name = "Module1"
Public X() As Double
Public Y() As Double
Public Z() As Double
Const Nmax = 7 '最大点数
Const Nmin = 3 '最小点数
Public Sxmin As Double
Public Sxmax As Double
Public Sym
www.eeworm.com/read/378102/9250881
c libout.c
#include
#include "string.h"
#define LEN sizeof(struct book)
#define LEN1 sizeof(struct list)
struct book
{char name[10];
int k;}num;
struct list
{char lname[10];
char passw[6];
www.eeworm.com/read/378041/9253228
m 17-1.m
I = checkerboard(10,2);
%棋盘图像
[m n]=size(I);
J=[];
for i=1:m
value=I(i,1);
num=1;
for j=2:n
if I(i,j)==value
num=num+1;
else
J=[J num val
www.eeworm.com/read/378038/9253401
m example6_1.m
%首先装载一原始信号
load nearbrk;
s=nearbrk;
%===========================
%画出该信号的波形图
subplot(4,2,1);
plot(s);
Ylabel('s');
title('原始信号s和信号的近似a、细节d');
%===========================
%用小波
www.eeworm.com/read/181297/9260297
cpp sf.cpp
# include
# include
# include
# include
# define MAX 10001
void values(int num, int A[])
{
int i;
srand(unsigned(time(NULL)));
for(i=1;i
www.eeworm.com/read/377814/9262051
m chap3_1.m
%Expert PID Controller
clear all;
close all;
ts=0.001;
sys=tf(5.235e005,[1,87.35,1.047e004,0]);
dsys=c2d(sys,ts,'z');
[num,den]=tfdata(dsys,'v');
u_1=0.0;u_2=0.0;u_3=0.0;
y_1=0;y_2=0;y_3=0
www.eeworm.com/read/181256/9262836
h com.h
// ----------------------------------------------------------------------------
// ATMEL Microcontroller Software Support - ROUSSET -
// --------------------------------------------
www.eeworm.com/read/377730/9263873
m myga.m
function [f,x]=myga(num,bounds,N,CP,P)
%[f,x]=ga(num,bounds,fun,N,CP,P)
%[f,x]=myga([],bounds,[],[],[])
%该遗传算法适用于：
% 目标函数为求最大值，且解非负整数解
%bounds 边界约束
%Myfun 为目标函数
%num
www.eeworm.com/read/181133/9273569
y bis.y
/* Reverse polish notation calculator. */
%{
#define YYSTYPE double
#include
#include
%}
%token NUM
%% /* Grammar rules and actions follow */
input: /* empty */
www.eeworm.com/read/180711/9297377
txt 11-20.txt
经典c程序100例==11--20
【程序11】
题目：古典问题：有一对兔子，从出生后第3个月起每个月都生一对兔子，小兔子长到第三个月
后每个月又生一对兔子，假如兔子都不死，问每个月的兔子总数为多少？
1.程序分析： 兔子的规律为数列1,1,2,3,5,8,13,21....
2.程序源代码：
#include "stdio.h"
#include "conio.h"
m ...