代码搜索：Num

找到约 10,000 项符合「Num」的源代码

代码结果 10,000
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c 1094.c

#include #define MAX 1000 int main() { int n,ca=0,cb,num,ans[MAX]={0}; while(scanf("%d",&n)==1) { for(cb=0;cb
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cpp 1406 完数.cpp

/* 1406 完数 Time Limit : 1000 ms Memory Limit : 32768 K Output Limit : 256 K 15 MS 344 KB 874 B GUN C++ */ #include #include using namespace std; const int Max=100
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cpp 1106 排序.cpp

/* 1106 排序 Time Limit : 1000 ms Memory Limit : 32768 K Output Limit : 5120 K GUN C++ */ #include #include #include using namespace std; const int SMAX=100
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cpp 1394 minimum inversion number.cpp

#include using namespace std; int num[5001]; int imin,n; int main() { int i,j,t; while( scanf("%d",&n)!=EOF )//输入的数字范围 0 ~ n-1 { for(i=0;i
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cpp 1216 assistance required.cpp

#include using namespace std; int luck[3100],len; bool num[17501]; void cal() { int i,j,k,t; luck[len++]=2; for(j=1;j
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cpp 1303 doubles.cpp

/* 1303 Doubles Time Limit : 1000 ms Memory Limit : 32768 K Output Limit : 256 K GUN C++ */ #include using namespace std; const int len=15; int num[len],now; bool Find(in
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cpp 1280 前m大的数.cpp

#include #include using namespace std; int num[3001]; int pplus[10001]; int main() { int i,j,n,m,max,t; while( scanf("%d %d",&n,&m)!=EOF ) { memset(pplus,0,sizeof
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cpp 1412 {a} + {b}.cpp

/* 1412 {A} + {B} Time Limit : 5000 ms Memory Limit : 32768 K Output Limit : 256 K GUN C++ */ #include using namespace std; const int nmMax=20000; int num[nmMax]={0},temp[nm
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c 1003n.c

/* 1003 Max Sum Time Limit : 1000 ms Memory Limit : 32768 K Output Limit : 1024 K GUN C input 4 -6 -8 0 -3 output 0 3 3 */ #include #include #define T 20 #define N
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c 2027.c

/* 2027 统计元音 Time Limit : 1000 ms Memory Limit : 32768 K Output Limit : 256 K GUN C */ #include #include char str[101]; int num[5]; int main( ) { int n; int i,len;
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