代码搜索:Microphone array
找到约 10,000 项符合「Microphone array」的源代码
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www.eeworm.com/read/180734/9296280
cpp array_init.cpp
/*
* This file contains code from "C++ Primer, Fourth Edition", by Stanley B.
* Lippman, Jose Lajoie, and Barbara E. Moo, and is covered under the
* copyright and warranty notices given in that
www.eeworm.com/read/180734/9296389
cpp copy_array.cpp
/*
* This file contains code from "C++ Primer, Fourth Edition", by Stanley B.
* Lippman, Jose Lajoie, and Barbara E. Moo, and is covered under the
* copyright and warranty notices given in that
www.eeworm.com/read/180734/9296829
cpp copy_array.cpp
/*
* This file contains code from "C++ Primer, Fourth Edition", by Stanley B.
* Lippman, Jose Lajoie, and Barbara E. Moo, and is covered under the
* copyright and warranty notices given in that
www.eeworm.com/read/179954/9329380
cpp array1.cpp
/* The following code example is taken from the book
* "The C++ Standard Library - A Tutorial and Reference"
* by Nicolai M. Josuttis, Addison-Wesley, 1999
*
* (C) Copyright Nicolai M. Josutti
www.eeworm.com/read/373603/9448516
c array_inv.c
/*将数组a中n个整数按相反顺序存放*/
/*解此题的算法为,将a[0]与a[n-1]对换,再将a[1]与a[n-2]对换……*/
/*直到将a[int(n-1)/2]与a[n-int ((n-1)/2)-1]对换。*/
/*今用循环处理此问题,设两个“位置指示变量”i和j,i的初值为0,j的初值为n-1.*/
/*将a[i]与a[j]交换,然后使i的值加1,j的值减1,再将a[i]与a[
www.eeworm.com/read/373397/9456871
c sum_array.c
/*
* $Id: sum_array.c,v 1.2 2002/04/11 23:51:22 ali Exp $
*
*
* NAME:
* sum_array.c
*
* PURPOSE:
* This C function is used to demonstrate how to read an IDL vector.
* It calcu
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c string_array.c
/*$Id: string_array.c,v 1.4 2002/04/11 23:51:22 ali Exp $
*
*
* NAME:
*
* string_array.c
*
* PURPOSE:
* This C function is used to demonstrate how to read an array of
* IDL st
www.eeworm.com/read/177055/9472178
js menu_array.js
/*
DHTML Menu version 3.3.19
Written by Andy Woolley
Copyright 2002 (c) Milonic Solutions. All Rights Reserved.
Plase vist http://www.milonic.co.uk/menu or e-mail menu3@milonic.com
You may u
www.eeworm.com/read/176602/9490664
m array_core.m
function y=array_core(h1,h2)
% array plot author: Mohamed Hamed awida
% in general AFn= 1/N * sin(N/2*epsi)/sin(epsi/2)
% where epsi=k*d*cos(theta)+beta but k=2*pi/lamda
% epsi=2*pi*
www.eeworm.com/read/371703/9541057
m bounded_array.m
function [x,ier]=bounded_array(x,lowerx,upperx)
% Modify array "x" in such a way that its entries do not exceed "upperx"
% and are not below "lowerx".
%
% Written by: E. Rietsch: October 21, 2006