代码搜索结果

clear all npts = 2000; del = 1/2000; t = 0:del:1; inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t); X0 = [1,.1,.01]'; % it is assumed that the measurement vector H=[1,0,0] % this is the

clear all npts = 2000; del = 1/2000; t = 0:del:1; inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t); X0 = [1,.1,.01]'; % it is assumed that the measurement vector H=[1,0,0] % this is the

clear all npts = 2000; del = 1/2000; t = 0:del:1; inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t); X0 = [1,.1,.01]'; % it is assumed that the measurement vector H=[1,0,0] % this is the

clear all npts = 2000; del = 1/2000; t = 0:del:1; inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t); X0 = [1,.1,.01]'; % it is assumed that the measurement vector H=[1,0,0] % this is the

clear all npts = 2000; del = 1/2000; t = 0:del:1; inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t); X0 = [1,.1,.01]'; % it is assumed that the measurement vector H=[1,0,0] % this is the

% User Defined Component pmu % Created with PSAT v1.3.3 % % Date: 04-Mar-2005 19:39:48 % Struct: Comp Comp.init(1,1) = 0; Comp.descr = 'Phasor measurement unit'; Comp.name = 'pmu'; Comp.shunt(1,

# {100} (100) [0] pm_measure_dlg.Label Measure Definition 测量定义 # [1] name_layout.Label Name 名称 # [2] name.Value Measure1 测量1 # [3] type.Label Type 类型 # [4] measure_type.HelpText Select measurement

clear all npts = 2000; del = 1/2000; t = 0:del:1; inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t); X0 = [1,.1,.01]'; % it is assumed that the measurement vector H=[1,0,0] % this is the

发信人: ardu (阿堵), 信区: DataMining 标 题: What the "lift" means in association mining 发信站: 南京大学小百合站 (Thu Dec 12 12:21:34 2002) In association discovery: The third measurement is called lift. The l

clear all npts = 2000; del = 1/2000; t = 0:del:1; inp = (1+.2 .* t + .1 .*t.^2) + cos(2. * pi * 2.5 .* t); X0 = [1,.1,.01]'; % it is assumed that the measurement vector H=[1,0,0] % this is the