代码搜索：Matrix
找到约 10,000 项符合「Matrix」的源代码
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www.eeworm.com/read/344814/11857802
m myhilb1.m
function[A,B]=myhilb(n,m)
%问题：生成一个Hilbert矩阵，该矩阵是一个n×m矩阵，它的第i行
%第j列的元素为1/(i+j-1)。如果想在编写的函数中实现下面几点：
%1）如果只给出一个输入参数，则会自动生成一个方阵，即有m=n
%2）如果想返回两个参数A和B，则返回的B矩阵为A矩阵的平方，
% 即B=A'A
%3)在函数中给出合适的帮助信息，包括基本 ...
www.eeworm.com/read/344562/11872333
m uy2hblk.m
% UY2HBLK - From data to impulse response. (Block algorithm)
%
% [h, delta] = uy2hblk(u, y, lmax, delta)
%
% U,Y - input (TxM matrix) and output (TxP matrix)
% LMAX - upper bound for the system lag
%
www.eeworm.com/read/155424/11874657
java eigenvaluedecomposition.java
package Jama;
import Jama.util.*;
/** Eigenvalues and eigenvectors of a real matrix.
If A is symmetric, then A = V*D*V' where the eigenvalue matrix D is
diagonal and the eigenvecto
www.eeworm.com/read/258131/11882790
m mpdecode.m
% MpDecode decodes a block code (e.g. LDPC) using the message passing algorithm.
%
% The calling syntax is:
% [output, errors] = MpDecode(input, H_rows, H_cols, [max_iter], [dec_type], [r_scal
www.eeworm.com/read/257911/11907029
m makeay.m
function [Ay, by] = makeAy(baseMVA, ng, gencost, pgbas, qgbas, ybas)
% makeAy: Make the A matrix and RHS for the CCV formulation.
%
% [Ay, by] = makeAy(baseMVA, ng, gencost, pgbas, qgbas, ybas) con
www.eeworm.com/read/154843/11923591
m ldatrace.m
function [a,f,B,W]=ldatrace(b,w,n,c)
%LDATRACE Calculates an LDA transform to maximize trace discriminant [a,f,B,W]=(b,w,n,c)
% If a feature vector X can come from one of several class and W and B a
www.eeworm.com/read/343762/11928522
m mvaar.m
function [x,e,Kalman,Q2] = mvaar(y,p,UC,mode,Kalman)
% Multivariate (Vector) adaptive AR estimation base on a multidimensional
% Kalman filer algorithm. A standard VAR model (A0=I) is implemented. The
www.eeworm.com/read/154760/11928876
m tutor1.m
% ADSP Toolbox: Version 2.0
% For use with "Analog and Digital Signal Processing", 2nd Ed.
% Published by PWS Publishing Co.
%
% Ashok Ambardar, EE Dept. MTU, Houghton, MI 49931, USA
% http://
www.eeworm.com/read/154488/11950767
m myhilb.m
function[A,B]=myhilb(n,m)
% MYHILB 生成一个Hilbert矩阵
% [A,B]=myhilb(n,m)
% where
% n,m are size of the Hilbert matrix,if only one
% argument given,then a square matrix is generated
% A is the Hil
www.eeworm.com/read/154488/11950781
m myhilb1.m
function[A,B]=myhilb(n,m)
%问题：生成一个Hilbert矩阵，该矩阵是一个n×m矩阵，它的第i行
%第j列的元素为1/(i+j-1)。如果想在编写的函数中实现下面几点：
%1）如果只给出一个输入参数，则会自动生成一个方阵，即有m=n
%2）如果想返回两个参数A和B，则返回的B矩阵为A矩阵的平方，
% 即B=A'A
%3)在函数中给出合适的帮助信息，包括基本 ...