代码搜索：MATLAB
找到约 10,000 项符合「MATLAB」的源代码
代码结果 10,000
www.eeworm.com/read/432455/8604627
txt readme.txt
Kalman filter toolbox written by Kevin Murphy, 1998.
See http://www.ai.mit.edu/~murphyk/Software/kalman.html for details.
Installation
------------
1. Install KPMtools from http://www.ai.mit.edu/~mu
www.eeworm.com/read/388439/8609614
m fil.m
function [out]=fil(in,f);
%
% Filters the data using a first order filter
%
% [out]=fil(in,f);
%
% f is a vector containing the filter constants
%
% Updated to use MATLAB's built in filter rou
www.eeworm.com/read/388419/8611218
txt pso.txt
基本粒子群优化算法<mark>Matlab</mark>源程序
这个程序就是最基本的粒子群优化算法程序，用<mark>Matlab</mark>实现，非常简单。只有几十行代码。正所谓一分钱一分货啊，优化效果不总是令人满意。我还有几个改进的粒子群优化算法版本，这一段时间会陆续发上来。
下面是主函数的源程序，优化函数则以m文件的形式放在fitness.m里面，对不同的优化函数只要修改fitness.m就可以了通用性很强。
...
www.eeworm.com/read/288527/8626966
m fil.m
function [out]=fil(in,f);
%
% Filters the data using a first order filter
%
% [out]=fil(in,f);
%
% f is a vector containing the filter constants
%
% Updated to use MATLAB's built in filter rou
www.eeworm.com/read/388000/8642649
dat bookinfo.dat
[General Information]
书名=MATLAB工程数学
作者=
页数=498
SS号=0
出版日期=
Vss号=58801754
www.eeworm.com/read/287953/8657687
c sin1500matl.c
//Sin1500MATL.c Generates sine from table created with MATLAB
#include "sin1500.h" //sin(1500) created with MATLAB
short i=0;
interrupt void c_int11()
{
output_sample(sin1500[i]); //o
www.eeworm.com/read/287843/8665307
m ip_01_01.m
% MATLAB script for Illustrative Problem 1, Chapter 1.
clear
n=[-20:1:20];
x=abs(sinc(n/2));
stem(n,x);
www.eeworm.com/read/287843/8665418
m ip_04_04.m
% MATLAB script for Illustrative Problem 4.4.
clear
echo on ;
a=[-10,-5,-4,-2,0,1,3,5,10];
for i=1:length(a)-1
y(i)=centroid('normal',a(i),a(i+1),0.001,0,1);
echo off ;
end
www.eeworm.com/read/431613/8665619
m ip_04_04.m
% MATLAB script for Illustrative Problem 4.4.
echo on ;
a=[-10,-5,-4,-2,0,1,3,5,10];
for i=1:length(a)-1
y(i)=centroid('normal',a(i),a(i+1),0.001,0,1);
echo off ;
end
www.eeworm.com/read/431596/8666318
m ip_01_01.m
% MATLAB script for Illustrative Problem 1, Chapter 1.
n=[-20:1:20];
x=abs(sinc(n/2));
stem(n,x);