代码搜索：Loop
找到约 10,000 项符合「Loop」的源代码
代码结果 10,000
www.eeworm.com/read/340289/12167530
asm prog47g.asm
; PROG47G - Working through the Electronic Breakout Box
;
;
; Start Taking User Input.
;
; PROG47G - Start Taking Serial Input/Displaying it on the LCD.
;
; PROG47F - Get and Set the Da
www.eeworm.com/read/151303/12222108
lst led.lst
A51 MACRO ASSEMBLER LED 05/04/2004 08:20:14 PAGE 1
MACRO ASSEMBLER A51 V7.02
OBJECT MODULE PLACED IN LED.OBJ
ASSEMBLER INVO
www.eeworm.com/read/339483/12230566
sh for-loopcmd.sh
#!/bin/bash
# for-loopcmd.sh: for-loop with [list]
#+ generated by command substitution.
NUMBERS="9 7 3 8 37.53"
for number in `echo $NUMBERS` # for number in 9 7 3 8 37.53
do
echo -n "$number "
www.eeworm.com/read/339382/12239719
cpp splint.cpp
void splint(double xa[], double ya[], double y2a[], int n, double& x, double& y)
{
int klo,khi,k;
double h,a,b,aaa,bbb;
klo = 1;
khi = n;
loop: if (khi - klo > 1 )
{
k = (khi +
www.eeworm.com/read/150655/12278609
cpp splint.cpp
void splint(double xa[], double ya[], double y2a[], int n, double& x, double& y)
{
int klo,khi,k;
double h,a,b,aaa,bbb;
klo = 1;
khi = n;
loop: if (khi - klo > 1 )
{
k = (khi +
www.eeworm.com/read/338615/12291941
asm vectors_11.asm
*Vectors_11.asm Vector file for interrupt-driven program
.ref _c_int11 ;ISR used in C program
.ref _c_int00 ;entry address
.sect "vectors" ;section for vectors
RESET_R
www.eeworm.com/read/338524/12295113
m mulms.m
% ==========================================================
%
% Neural Networks A Classroom Approach
% Satish Kumar
% Copyright Tata McGraw Hill, 2004
www.eeworm.com/read/338523/12298660
output
version 4.3, 26 Jan 1989
# Problem number 1
nsource 8
ndest 6
sources
12 7 6 11 10 4 4 3
dests
13 11 9 7 3 14
costs
1 3 8
www.eeworm.com/read/338459/12306380
txt 1seg.txt
;8MHZ
;一只数码管显示出0-9十个数字
;电路连接为:164数据脚接RXD,而时针脚接TXD,TXD供时针信号
;P1中任一脚用来控制数码管的导通
;164数据一送出,不会因为再没有送数据而没有输出
;而还是保留最后的数据
org 00h
mov scon,#00000000b ;设定UART方式MODE0
start:
mov dptr,#table
www.eeworm.com/read/150072/12317566
cpp splint.cpp
void splint(double xa[], double ya[], double y2a[], int n, double& x, double& y)
{
int klo,khi,k;
double h,a,b,aaa,bbb;
klo = 1;
khi = n;
loop: if (khi - klo > 1 )
{
k = (khi +