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找到约 10,000 项符合 Logic Analyzer 的代码

logic.in8

10 10 10 A B C D E F G H I J A: B is guilty. B: C is guilty. C: D is guilty. D: E is guilty. E: F is guilty. F: G is guilty. G: H is guilty. H: I love you! I: I am not guilty. J: I

logic.in5

10 7 20 A AA AAA AAAA AAAAA AAAAAA AAAAAAA AAAAAAAA AAAAAAAAA AAAAAAAAAA A: Today is Monday. AA: Today is Monday. AAA: Today is Monday. AAAA: Today is Monday. AAAAA: Today is Monday. A

logic.in1

1 0 2 A A: I am guilty. A: I am not guilty.

logic.in4

4 1 5 KYO IORI CHIZURU OROCHI KYO: I am guilty. IORI: I am not guilty. CHIZURU: OROCHI is guilty. OROCHI: Today is Monday. OROCHI: I am guilty.

logic.in3

7 3 10 MONDAY TUESDAY WEDNESDAY THURSDAY FRIDAY SATURDAY SUNDAY MONDAY: Today is Monday. TUESDAY: Today is Tuesday. WEDNESDAY: Today is Wednesday. THURSDAY: Today is Thursday. FRIDAY: MOND

logic.c

# include void main() { /* 定义一个整数类型的变量,用来存放后面算式的值 */ int logic; int a = 1; int b = 2; int c = 3; logic = a+b>c&&b=

logic.java

package com.today.prodect.model; import java.io.FileNotFoundException; import java.sql.Connection; import java.sql.PreparedStatement; import java.sql.ResultSet; import java.sql.SQLException; i

logic.c

logic (a, b) int *a, b; { if (*a & 123) b = 1; if (*a & ~222) b = 2; if (124 & *a) b = 3; if (~111 & *a) b = 4; if (~*a & 23) b = 1; if (~*a & ~22) b = 2; i

logic.java

package logic; import java.util.Vector; import javax.swing.JOptionPane; import view.mainUI; import dboperate.dboperate; public class logic { dboperate db=new dboperate(); //--------

logic.txt

Least Enlargement: The idea is to find a rectangle that needs to be least enlarged in order to accommodate the given rectangle. Enlargement in the sense that the sides of the rectangle is so increa