代码搜索:LP

找到约 9,457 项符合「LP」的源代码

代码结果 9,457
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m ideal_lp.m

function hd=ideal_lp(wc,M); alpha=(M-1)/2; n=[0:1:(M-1)]; m=n-alpha+eps; hd=sin(wc*m)./(pi*m);
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gif lp7.gif

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cof lp33.cof

//lp33.cof low pass FIR filter coefficients designed using fir1(32,0.45) #define N 33 // number of coefficients float h[N] = { -9.3509933339593076e-004, 1.3324942475194321e-003
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m ideal_lp.m

function hd=ideal_lp(wc,N); alpha=(N-1)/2; %计算冲击脉冲响应的相位 n=[0:1:(N-1)]; m=n-alpha+eps; %加入eps,确保分母是非零数 hd=sin(wc*m)./(pi*m);
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m ideal_lp.m

function hd = ideal_lp(wc,M); % 理想低通滤波器计算 % -------------------------------- % [hd] = ideal_lp(wc,M) % hd = 0 to M-1之间的理想脉冲响应 % wc = 截止频率(弧度) % M = 理想滤波器的长度 % alpha = (M-1)/2; n = [0:1:(
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dat lp_coef.dat

#pragma DATA_SECTION(LP_coef, "lms_data"); int LP_coef[48]={ -6, 28, 46, 27, -35, -100, -93, 26, 191, 240, 52, -291, -497, -278, 337, 888, 773,
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m ideal_lp.m

function hd = ideal_lp(wc,M); % Ideal LowPass filter computation % -------------------------------- % [hd] = ideal_lp(wc,M) % hd = ideal impulse response between 0 to M-1 % wc = cutoff frequenc
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m ideal_lp.m

function hd=ideal_lp(Wc,N) % compute the ideal lowpass fiter unit pulse respondence hd(n) % wc: cutoff frequency % N: window length % hd: unit pulse respondence alpha = (N-1)/2; n=0:1:N-1; m
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cof lp2000.cof

//lp2000.cof IIR lowpass coefficients file, cutoff frequency 2 kHz #define stages 4 //number of 2nd-order stages int a[stages][3] = { //numerator coefficients {304, 608, 304}, /
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cof lp55.cof

//LP55.COF Coefficients for FIR lowpass filter. Cutoff frequency Fs/4 = 2 kHz float h[55]={3.6353E-003,-1.1901E-003,-4.5219E-003, 2.6882E-003, 5.1775E-003, -4.7252E-003,-5.4097E-003, 7.2940E-