代码搜索:Inverted
找到约 874 项符合「Inverted」的源代码
代码结果 874
www.eeworm.com/read/294145/3920064
m seq_to_s.m
function [S] = seq_to_S( seq, L );
% This makes it more easy, as seq is supposed to be
% s11, s12, s13, ...
% s21, s22, s23, ...
% and the resulting matrix is supposed to be inverted...
seq = fliplr(
www.eeworm.com/read/449679/7498351
nec tr-line.nec
CM Inverted V for 80 Mtr with transmission line
CE
SY hgh=20 ' Height
SY len=20 ' Wire length
SY ang=110 ' Angle between wires
SY Z=len*cos(ang/2), X=len*sin(ang/2) ' Get Z and X dista
www.eeworm.com/read/449679/7498370
nec 36inv.nec
CM Inverted V for 80 Mtr.
CE
SY hgh = 21 ' Height
SY len = 19.722 ' Wire length
SY ang=110 ' Angle between wires
SY Z=len*cos(ang/2),X=len*sin(ang/2) ' Get delta-Z and -X distances
'
www.eeworm.com/read/180137/5291160
3 odeum.3
.TH ODEUM 3 "2003-11-27" "Man Page" "Quick Database Manager"
.SH NAME
Odeum \- the inverted API of QDBM
.SH SYNOPSIS
.PP
.B #include
.br
.B #include
.br
.B #include
.br
www.eeworm.com/read/244381/12869680
m hinf_pend.m
% H_infinity design of the triple inverted pendulum
%
nmeas = 6;
ncon = 2;
gmin = 0;
gmax = 10;
tol = 0.001;
hin_ic = sel(pend_ic,[9:19],[9:19]);
[K_hin,clp,gfin] = hinfsyn(hin_ic,nmeas,ncon,g
www.eeworm.com/read/244381/12869705
m mu_pend.m
% mu-analysis of the triple inverted pendulum
% closed-loop system
%
clp_ic = starp(pend_ic,K,6,2);
omega = logspace(-1,4,100);
clp_g = frsp(clp_ic,omega);
%
% robust stability
rob_stab = sel(
www.eeworm.com/read/101167/15842889
c 1820_1.c
// 1820_1.C PIC12C672, CCS PCM
//
// Measures temperature using a Dallas DS1820 on GP2 and displays result
// using RS232 serial (9600 inverted) on GP1.
// PIC12C672
// +5VDC
//
www.eeworm.com/read/460712/7105614
m chap8_7design.m
%H Infinity Controller Design based on LMI for Double Inverted Pendulum
clear all;
close all;
A=[0,0,0,1.0,0,0;
0,0,0,0,1.0,0;
0,0,0,0,0,-1.0;
0,-3.7864,0.2009,-4.5480,0.0037,-0.0017;
www.eeworm.com/read/439271/7713144
m chap8_7design.m
%H Infinity Controller Design based on LMI for Double Inverted Pendulum
clear all;
close all;
A=[0,0,0,1.0,0,0;
0,0,0,0,1.0,0;
0,0,0,0,0,-1.0;
0,-3.7864,0.2009,-4.5480,0.0037,-0.0017;
www.eeworm.com/read/271348/10999769
m nn_pidf.m
function dx=dym(t,x,flag,para)
global A B C D
u=para;
dx=zeros(4,1);
%State equation for one link inverted pendulum
%dx=A*x+B*u;
dx=[x(2);
(x(4)^2*sin(x(3))-3.67875*sin(2*x(3))-50.9784*x