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crc_routines.h

/* | | Copyright disclaimer: | This software was developed at the National Institute of Standards | and Technology by employees of the Federal Government in the course | of their official d

phd_connect.c

/* Program to login into PHD PHD = Process History database, a Honeywell-database to store chemical plant data Author : Hans Vereecken BASF Antwerp 003235613411 hans.vereecken@notes.basant.be

viterbi_encoder.m

function [channel_input]=viterbi_encoder(G,k,coder_input) %k for input number channel_input=[]; %n for output number n=size(G,1); G_2=size(G,2); if rem(size(G,2),k)~=0 error('Size of G a

viterbi_encoder.m

function [channel_input]=viterbi_encoder(G,k,coder_input) %k for input number channel_input=[]; %n for output number n=size(G,1); G_2=size(G,2); if rem(size(G,2),k)~=0 error('Size of G a

viterbi_encoder.m

%该函数实现维特比译码 function [channel_input]=viterbi_encoder(G,k,coder_input) %G为生成矩阵,k为并行输入端的个数,code_input为编码器输入序列 %k for input number channel_input=[]; %初始化编码器输出 %n for output number n=size(G,

viterbi_encoder.m

function [channel_input]=viterbi_encoder(G,k,coder_input) %k为输入位数 channel_input=[]; n=size(G,1);%n为输出位数,生成矩阵G的行数 G_2=size(G,2);%G_2 生成矩阵G的列数 %检查生成矩阵的列数和输入序列是否是k的倍数 if rem(size(G,2),k)~=0

viterbi_encoder.m

function [channel_input]=viterbi_encoder(G,k,coder_input) %k为输入位数 channel_input=[]; n=size(G,1);%n为输出位数,生成矩阵G的行数 G_2=size(G,2);%G_2 生成矩阵G的列数 %检查生成矩阵的列数和输入序列是否是k的倍数 if rem(size(G,2),k)~=0

viterbi_encoder.m

function [channel_input]=viterbi_encoder(G,k,coder_input) %k为输入位数 channel_input=[]; n=size(G,1);%n为输出位数,生成矩阵G的行数 G_2=size(G,2);%G_2 生成矩阵G的列数 %检查生成矩阵的列数和输入序列是否是k的倍数 if rem(size(G,2),k)~=0

viterbi_encoder.m

function [channel_input]=viterbi_encoder(G,k,coder_input) %k for input number channel_input=[]; %n for output number n=size(G,1); G_2=size(G,2); if rem(size(G,2),k)~=0 error('Size of G a

viterbi_encoder.m

%viterbi编码 function [channel_input]=viterbi_encoder(G,k,coder_input) %k for input number channel_input=[]; %n for output number n=size(G,1); G_2=size(G,2); if rem(size(G,2),k)~=0 % rem 使取余的意