代码搜索:FREE 有哪些应用?

找到约 10,000 项符合「FREE 有哪些应用?」的源代码

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c 4rinv.c

#include "stdlib.h" #include "math.h" #include "stdio.h" int rinv(a,n) int n; double a[]; { int *is,*js,i,j,k,l,u,v; double d,p; is=malloc(n*sizeof(int)); js=mallo
www.eeworm.com/read/414450/11111671

muse p04.muse

#title P04: 混合三种背包问题 * 问题 如果将[[P01]]、[[P02]]、[[P03]]混合起来。也就是说,有的物品只可以取一次(01背包),有的物品可以取无限次(完全背包),有的物品可以取的次数有一个上限(多重背包)。应该怎么求解呢? * 01背包与完全背包的混合 考虑到在[[P01]]和[[P02]]中给出的伪代码只有一处不同,故如果只有两类物品:一类物品只能取一次,另 ...
www.eeworm.com/read/267227/11189241

c 6gaus.c

#include "stdlib.h" #include "math.h" #include "stdio.h" int gaus(a,b,n) int n; double a[],b[]; { int *js,l,k,i,j,is,p,q; double d,t; js=malloc(n*sizeof(int)); l=1
www.eeworm.com/read/267227/11189325

c 4rinv.c

#include "stdlib.h" #include "math.h" #include "stdio.h" int rinv(a,n) int n; double a[]; { int *is,*js,i,j,k,l,u,v; double d,p; is=malloc(n*sizeof(int)); js=mallo
www.eeworm.com/read/267227/11189387

c 6gjdn.c

#include "stdlib.h" #include "math.h" #include "stdio.h" int gjdn(a,b,n,m) int n,m; double a[],b[]; { int *js,l,k,i,j,is,p,q; double d,t; js=malloc(n*sizeof(int));
www.eeworm.com/read/267227/11189429

c 6gaus.c

#include "stdlib.h" #include "math.h" #include "stdio.h" int gaus(a,b,n) int n; double a[],b[]; { int *js,l,k,i,j,is,p,q; double d,t; js=malloc(n*sizeof(int)); l=1
www.eeworm.com/read/267227/11189436

c 6ggje.c

#include "stdlib.h" #include "math.h" #include "stdio.h" int ggje(a,n,b) int n; double a[],b[]; { int *js,i,j,k,is,u,v; double d,t; js=malloc(n*sizeof(int)); for (
www.eeworm.com/read/267227/11189496

c 4rinv.c

#include "stdlib.h" #include "math.h" #include "stdio.h" int rinv(a,n) int n; double a[]; { int *is,*js,i,j,k,l,u,v; double d,p; is=malloc(n*sizeof(int)); js=mallo
www.eeworm.com/read/267227/11189648

c 4rinv.c

#include "stdlib.h" #include "math.h" #include "stdio.h" int rinv(a,n) int n; double a[]; { int *is,*js,i,j,k,l,u,v; double d,p; is=malloc(n*sizeof(int)); js=mallo
www.eeworm.com/read/267227/11189652

c 4cinv.c

#include "stdlib.h" #include "stdio.h" int cinv(ar,ai,n) int n; double ar[],ai[]; { int *is,*js,i,j,k,l,u,v,w; double p,q,s,t,d,b; is=malloc(n*sizeof(int)); js=malloc