代码搜索：Exercise
找到约 10,000 项符合「Exercise」的源代码
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java ex2.java
// interfaces/Ex2.java
// TIJ4 Chapter Interfaces, Exercise 2, page 315
// Create a class as abstract without including any abstract methods, and verify
// that you cannot create any instances of t
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java testex5.java
// interfaces.TestEx5.java
// TIJ4 Chapter Interfaces, Exercise 5, page 320
// Create an interface containing three methods, in its own package. Implement it
// in another package.
/* Solution inc
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java doctest.java
// object.DocTest.java
// TIJ4 Chapter Object, Exercise 12, page 90
/* Find the code for the second version of HelloDate.java, which is the simple
* comment documentation example. Execute Javadoc o
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txt spmsgb102.txt
Subject: ad : stop pain fast !
stop pain fast : golf - tenni - exercise with no pain ! hello ! = 20 my name be pat . i ' m an avid tennis player and walker . i suffer from shoulder pain for year . no
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dat readme.dat
README file for Fence2 directory
iSIGHT v6.0 Training Class
Files needed for the exercise in the training manual
(paths are relative to the isightTrn/Fence directory):
1- ./Fence.xls = Excel s
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readme
This directory contains the small example programs from Multimedia on
Linux.
Makefile - make file
README - this file
cdtester.c - program to exercise CD-ROM ioctl calls (not in book)
dsp_info - show
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cpp ex18_20.cpp
// Exercise 18.20: ex18_20.cpp
#include
using std::cout;
using std::cin;
using std::endl;
using std::boolalpha;
bool mystery( unsigned );
int main()
{
unsigned x;
co
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cpp ex18_19.cpp
// Exercise 18.19: ex18_19.cpp
// This program determines if a value is a multiple of X.
#include
using std::cout;
using std::cin;
using std::endl;
bool multiple( int );
int ma
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cpp ex03_50.cpp
// Exercise 3.50: ex03_50.cpp
// What does this program do?
#include
using std::cout;
using std::cin;
using std::endl;
int mystery( int, int ); // function prototype
int
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java trypolyline.java
// Chapter 6 Exercise 6
public class TryPolyLine {
public static void main(String[] args) {
// Create an array of coordinate pairs:
double[][] coords = { {1., 1.}, {1., 2.}, { 2.,