代码搜索:Exercise
找到约 10,000 项符合「Exercise」的源代码
代码结果 10,000
www.eeworm.com/read/329553/12949336
doc exercise1.doc
www.eeworm.com/read/242370/13009065
cpp string_exercise.cpp
/*
* This file contains code from "C++ Primer, Fourth Edition", by Stanley B.
* Lippman, Jose Lajoie, and Barbara E. Moo, and is covered under the
* copyright and warranty notices given in that
www.eeworm.com/read/242370/13009083
cpp cstring_exercise.cpp
/*
* This file contains code from "C++ Primer, Fourth Edition", by Stanley B.
* Lippman, Jose Lajoie, and Barbara E. Moo, and is covered under the
* copyright and warranty notices given in that
www.eeworm.com/read/140545/13076640
cpp exercise16.cpp
//: C04:Exercise16.cpp
#include
#include
#include
#include "../require.h"
using namespace std;
#define d(a) cout
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vi array exercise.vi
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vi cluster exercise.vi
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cpp exercise_7.cpp
/*
幂法求矩阵的特征值和特征向量
1. 初始化矩阵,向量,误差
2. 置u=0。
3. 求xr=>λ
4. 计算
Y=X/λ,X=AY
5. 若|λ-u|
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cpp exercise_1.cpp
#include
#include
#include
#define N 100000000
using namespace std;
double item(int n);
int main()
{
cout.precision(12);
int i=1,a[2]={0};
double X=1.0;
www.eeworm.com/read/323707/13325667
txt exercise 2.txt
/*第1题*/
SELECT Name, Year
FROM Title
WHERE CallNumber = SOME ( SELECT CallNumber
FROM Author
WhERE Lname = 'Churchill' )
/*第2题*/
SELECT Na
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mdl exercise1.mdl
Model {
Name "exercise1"
Version 6.6
MdlSubVersion 0
GraphicalInterface {
NumRootInports 0
NumRootOutports 2
Outport {
BusObject ""
Bu