代码搜索：Distance
找到约 8,736 项符合「Distance」的源代码
代码结果 8,736
www.eeworm.com/read/235440/14071852
plt distance.plt
set xrange [0:1]
set yrange [0:1]
set xlabel "Node Distance (r)"
set ylabel "Links Connected Ratio"
set ytics (0, 0.1, 0.2, 0.3, 0.4, 0.5, 0.6, 0.7, 0.8, 0.9, 1.0)
set xtics (0, 0.1, 0.2, 0.3,
www.eeworm.com/read/111650/15507180
cpp distance.cpp
/* The following code example is taken from the book
* "The C++ Standard Library - A Tutorial and Reference"
* by Nicolai M. Josuttis, Addison-Wesley, 1999
*
* (C) Copyright Nicolai M. Josutti
www.eeworm.com/read/111650/15507192
hpp distance.hpp
/* The following code example is taken from the book
* "The C++ Standard Library - A Tutorial and Reference"
* by Nicolai M. Josuttis, Addison-Wesley, 1999
*
* (C) Copyright Nicolai M. Josutti
www.eeworm.com/read/107504/15605629
cpp distance.cpp
/* The following code example is taken from the book
* "The C++ Standard Library - A Tutorial and Reference"
* by Nicolai M. Josuttis, Addison-Wesley, 1999
*
* (C) Copyright Nicolai M. Josutti
www.eeworm.com/read/107504/15605641
hpp distance.hpp
/* The following code example is taken from the book
* "The C++ Standard Library - A Tutorial and Reference"
* by Nicolai M. Josuttis, Addison-Wesley, 1999
*
* (C) Copyright Nicolai M. Josutti
www.eeworm.com/read/101912/15798120
cpp distance.cpp
/* The following code example is taken from the book
* "The C++ Standard Library - A Tutorial and Reference"
* by Nicolai M. Josuttis, Addison-Wesley, 1999
*
* (C) Copyright Nicolai M. Josutti
www.eeworm.com/read/101912/15798132
hpp distance.hpp
/* The following code example is taken from the book
* "The C++ Standard Library - A Tutorial and Reference"
* by Nicolai M. Josuttis, Addison-Wesley, 1999
*
* (C) Copyright Nicolai M. Josutti
www.eeworm.com/read/191902/8417197
m edit_distance.m
www.eeworm.com/read/291026/8444535
m eu_distance.m
function dist=Eu_distance(c1,state);
%本函数用来求c1与状态state
%对应星座点之间的欧式距离
A=state*pi/4;
c2=cos(A)+j*sin(A);
a=real(c1);
b=imag(c1);
c=real(c2);
d=imag(c2);
dist=sqrt((a-c)*(a-c)+(b-d)*(b-d));