代码搜索:Disc

找到约 1,656 项符合「Disc」的源代码

代码结果 1,656
www.eeworm.com/read/480611/6666988

cpp 4.12.cpp

/*求ax2+bx+c=0的方程的根*/ #include #include int main() { float a,b,c,disc,x1,x2,p,q; scanf("a=%f,b=%f,c=%f",&a,&b,&c); disc=b*b-4*a*c; p=-b/(2*a); q=sqrt(disc
www.eeworm.com/read/479440/6695448

java handlemouse.java

import java.awt.event.*; import java.awt.*; public class HandleMouse implements MouseListener,MouseMotionListener { TowerPoint [] pointA,pointB,pointC; TowerPoint startPoint=null,endPoint=
www.eeworm.com/read/264889/11295874

cpp 11_7.cpp

#include < iostream > #include < cmath > using namespace std; int main( ) { float a, b, c, disc; cout >a >>b >>c; if (a ==0) cerr
www.eeworm.com/read/263454/11362170

c symamgsavediag.c

#include #include #include #include #include #include #include double SYMAMGSAVEDIAG(size_t *Fparam, integer *n, i
www.eeworm.com/read/406868/11433658

m rs_base.m

%RS隐写分析方法中的最核心函数 %在此函数中求解出进行M和-M变换的R组合S组的数目参数 function [R,S,U,MR,MS,MU]=RS_base(a,bufsize) %l=length(a); %进行M伪装变换 并计算相应的参数 m=[1,0,1,0]; R=0; S=0; U=0; for i=1:bufsize/4 for m=1:4 b(m)=
www.eeworm.com/read/403957/11493815

idx lookup.idx

bib-0.htm=bibfs.htm chap1.htm=chap1fs.htm chap2.htm=chap2fs.htm chap3-0.htm=chap3fs.htm chap4-0.htm=chap4fs.htm chap5-0.htm=chap5fs.htm chap6.htm=chap6fs.htm chapA-0.htm=chapAfs.htm chapB-0.ht
www.eeworm.com/read/403957/11494033

htm leftbeh.htm

function loadApplet() { if(navigator.appName == "Netscape") { if(top._appletWindow == null || top._appletWindow.closed) { top._appletWindow =
www.eeworm.com/read/403957/11494421

idx lookup.idx

bib-0.htm=bibfs.htm chap1.htm=chap1fs.htm chap2.htm=chap2fs.htm chap3-0.htm=chap3fs.htm chap4-0.htm=chap4fs.htm chap5-0.htm=chap5fs.htm chap6.htm=chap6fs.htm chapA-0.htm=chapAfs.htm chapB-0.ht
www.eeworm.com/read/403957/11494640

htm leftbeh.htm

function loadApplet() { if(navigator.appName == "Netscape") { if(top._appletWindow == null || top._appletWindow.closed) { top._appletWindow =
www.eeworm.com/read/402088/11543243

java root.java

import java.lang.*; import java.io.*; public class Root{ public static void main(String args[]) throws IOException { double A,B,C,x1,x2,x,disc; String str="i"; BufferedReader br=new Buffere