代码搜索:Digit

找到约 4,689 项符合「Digit」的源代码

代码结果 4,689
www.eeworm.com/read/296467/8101682

c test44x_lcd01.c

#include char digit[10] = { 0xB7, /* "0" LCD segments a+b+c+d+e+f */ 0x12, /* "1" */ 0x8F, /* "2" */ 0x1F, /* "3" */ 0x3A, /* "4" */ 0x3D, /* "5" */ 0xBD, /* "6" *
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c test44x_lcd03.c

#include "msp430x44x.h" char digit[10] = { 0xB7, // "0" LCD segments a+b+c+d+e+f 0x12, // "1" 0x8F, // "2" 0x1F, // "3" 0x3A, // "4" 0x3D, // "5" 0xBD, // "6" 0x13, // "
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java array04.java

// =============== Program Description =============== // 程序名称: array04.java // 程序目的: 设计一个可容纳40位数的求n!程序 // Written By Kuo-Yu Huang. (WANT Studio.) // =============================================
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c matridemo.c

/* */ #include #define uchar unsigned char uchar code digit[16] = {0x3f,0x06,0x5B,0x4f,0x66,0x6d,0x7d,0x07,0x7f,0x6f,0xFF,0xFF, 0xFF,0xFF,0xFF,0xFF,};
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bak matridemo.c.bak

/* */ #include #define uchar unsigned char uchar code digit[16] = {0x06,0xFF,0xFF,0xFF, //数据表 0xFF,0xFF,0xFF,0xFF, 0xFF,0xFF,0xFF,0xFF,
www.eeworm.com/read/246404/12728436

pas ac1040.pas

program tju1040; const maxn=4999; var ok:array[0..9]of boolean; q,pre:array[1..maxn]of word; digit:array[1..maxn]of byte; v:array[0..maxn-1]of boolean; k,u,n,m,i,f,r:word; procedu
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pas ac1040.pas

program tju1040; const maxn=4999; var ok:array[0..9]of boolean; q,pre:array[1..maxn]of word; digit:array[1..maxn]of byte; v:array[0..maxn-1]of boolean; k,u,n,m,i,f,r:word; procedu
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java ex3.java

//import consoleReader.*; /** * @author sxjiang * E_mail: sxjiang@aust.edu.cn * nO:s103612005075 * Class:2005-11 * name:sxjiang */ public class Ex3 { public static void main(
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txt array01.c.txt

/*数组 实验 设计一个可容纳40位数的求n!的程序  */ /*===============================================*/ /*程序构思: */ /*依题意可得知,本程序所运用的数据结构为“数组”,*/ /*目的为运用数组来弥补整数数据类型有限的使用范围。*/ /*我们
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cpp xt3-16.cpp

#include using namespace std; int main () {char c; int letters=0,space=0,digit=0,other=0; cout