代码搜索:Difference

找到约 3,389 项符合「Difference」的源代码

代码结果 3,389
www.eeworm.com/read/388457/8608127

m p2_3.m

% Program P2_3 % Generate the input sequences clf; n = 0:40; a = 2;b = -3; x1 = cos(2*pi*0.1*n); x2 = cos(2*pi*0.4*n); x = a*x1 + b*x2; num = [2.2403 2.4908 2.2403]; den = [1 -0.4 0.75]; ic
www.eeworm.com/read/187617/8619158

21663

Xref: cantaloupe.srv.cs.cmu.edu soc.religion.christian:21663 Path: cantaloupe.srv.cs.cmu.edu!das-news.harvard.edu!noc.near.net!howland.reston.ans.net!agate!ames!pacbell.com!att-out!rutgers!igor.rutger
www.eeworm.com/read/288527/8625444

m calcbits.m

function [bits]=calcbits(bounds,precision) % function [bits]=calcbits(bounds,precision) % Determine the number of bits to represent a float number to the precision % provided. % % bits - the
www.eeworm.com/read/387887/8649532

m p2_3.m

% Program P2_3 % Generate the input sequences clf; n = 0:40; a = 2;b = -3; x1 = cos(2*pi*0.1*n); x2 = cos(2*pi*0.4*n); x = a*x1 + b*x2; num = [2.2403 2.4908 2.2403]; den = [1 -0.4 0.75]; ic
www.eeworm.com/read/430838/8723712

m calcbits.m

function [bits]=calcbits(bounds,precision) % function [bits]=calcbits(bounds,precision) % % Determine the number of bits to represent a float number to the precision % provided. % % bits - the nu
www.eeworm.com/read/429878/8784085

htm gradchek.htm

Netlab Reference Manual gradchek gradchek Purpose Checks a user-defined gradient function using finite differences. Synopsi
www.eeworm.com/read/385005/8824573

m delq.m

function dq=delq(Ts,Ta,rh) % DELQ: computes air-sea specific humidity difference. % dq=DELQ(Ts,Ta,rh) computes the specific humidity (kg/kg) difference % between the air (as determined by relati
www.eeworm.com/read/428269/8880427

m testwaveletkernel.m

% % this is a script for testing and looking into wavelet kernel % and different decompositions. % % clear all close all % this is the data N=50; x=linspace(0,1,N)'; % these are the
www.eeworm.com/read/428233/8881992

cpp 牛顿值多项式.cpp

#include #define N 4 void Difference(float *x,float *y,int n) { float *f; int k,i; f =new float[(n*sizeof(float))]; for(k=1;k
www.eeworm.com/read/186987/8886196

m p2_3.m

% Program P2_3 % Generate the input sequences clf; n = 0:40; a = 2;b = -3; x1 = cos(2*pi*0.1*n); x2 = cos(2*pi*0.4*n); x = a*x1 + b*x2; num = [2.2403 2.4908 2.2403]; den = [1 -0.4 0.75]; ic = [0 0]; %