代码搜索:Coding

找到约 9,366 项符合「Coding」的源代码

代码结果 9,366
www.eeworm.com/read/393716/2469136

txt cmakelists.txt

INCLUDE_DIRECTORIES(../mySTL include) ADD_LIBRARY(taocrypt src/aes.cpp src/aestables.cpp src/algebra.cpp src/arc4.cpp src/asn.cpp src/coding.cpp src/des.cpp src/dh.cpp src/dsa.cpp src/file.cpp s
www.eeworm.com/read/393713/2470472

txt cmakelists.txt

INCLUDE_DIRECTORIES(mySTL include) ADD_LIBRARY(taocrypt src/aes.cpp src/aestables.cpp src/algebra.cpp src/arc4.cpp src/asn.cpp src/coding.cpp src/des.cpp src/dh.cpp src/dsa.cpp src/file.cpp src/
www.eeworm.com/read/287849/8664408

txt arq6.txt

please input the message length to n: 384 please input the con_len to K: 6 你选择的编码深度所对应的穿孔矩阵及其它信息如下: M G1 G2 the punc_table the coding rate: 5 53 75 1 1 0 1 1 5/9 1 1 1 1
www.eeworm.com/read/287849/8664411

txt arq5.txt

please input the message length to n: 384 please input the con_len to K: 5 你选择的编码深度所对应的穿孔矩阵及其它信息如下: M G1 G2 the punc_table the coding rate: 4 23 35 1 1 1 1 1 5/9 1 1 0 1
www.eeworm.com/read/287849/8664413

txt arq4.txt

please input the message length to n: 384 please input the con_len to K: 4 你选择的编码深度所对应的穿孔矩阵及其它信息如下: M G1 G2 the punc_table the coding rate: 3 15 17 1 1 1 1 1 5/9 0 1 1 1
www.eeworm.com/read/299182/7881063

py a4.py

# -*- coding: cp936 -*- from math import sqrt #第四章----素数的家族 #《c趣味编程》30-35题 #21:44 2007-1-11 def z30(): #10000以内的素数是: print "10000以内的素数是:" m= filter(isP,range(2,1000)) print m,
www.eeworm.com/read/221611/14735788

m rsc_encoding.m

function [output1_bin,state1_int]=rsc_encoding(g1,st_t1,out_t1,info) %RSC coding for each channel %to get output and the last state of rsc encoder n=length(info); mem1=size(g1,2)-1; state1_int=1; ou
www.eeworm.com/read/472766/6865095

py sillab-usb.py

# -*- coding: utf-8 -*- import usb ID_VENDOR = 0x10C4 ID_PRODUCT = 0x0002 ID_INTERFACE = 0 EP_IN = 0x82 EP_OUT = 0x02 TIME_OUT = 200 def getDevice(device_nro): buses = usb.busses() devices
www.eeworm.com/read/187844/8596445

m dcode.m

function y=dcode(x,rd); % % Usage:y=dcode(x); BBI 2000,x为原码,y为微分编码,rd为初始参考相位,微分译码的过程为x=xor(y,[rd y(1:length(y)-1)]) % Differential Coding if nargin
www.eeworm.com/read/287849/8664383

txt arq.txt

please input the message length to n: 382 please input the con_len to K: 3 你选择的编码深度所对应的穿孔矩阵及其它信息如下: M G1 G2 the punc_table the coding rate: 2 5 7 1 1 0 1 1 5/9 1 1 1 1 1 2