代码搜索:Coding

找到约 9,366 项符合「Coding」的源代码

代码结果 9,366
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h state.h

//enum for one hot coding enum onehot_t { STATE_0 = 0, STATE_1 = 1, STATE_2 = 2, STATE_3 = 4, STATE_4 = 8, STATE_5 = 16, STATE_6 = 32 }; struct state_t { onehot_t state; int delay; uns
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am makefile.am

INCLUDES = -I../include -I../mySTL lib_LIBRARIES = libtaocrypt.a libtaocrypt_a_SOURCES = aes.cpp aestables.cpp algebra.cpp arc4.cpp asn.cpp \ bftables.cpp blowfish.cpp coding.cpp dh.cpp des.cpp
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h state.h

//enum for one hot coding enum onehot_t { STATE_0 = 0, STATE_1 = 1, STATE_2 = 2, STATE_3 = 4, STATE_4 = 8, STATE_5 = 16, STATE_6 = 32 }; struct state_t { onehot_t state; int delay; uns
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h vm_enc_defs.h

//视频宏块编码定义 #ifndef _VM_ENC_DEFS_H_ #define _VM_ENC_DEFS_H_ #include "vm_common_defs.h" #define I_VOP 0 /* vop coding modes */ #define P_VOP 1 #define B_VOP 2 #define SPRITE_VOP 3 #d
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py tux.py

# coding=gbk import struct, types, socket, io, threading, Queue, time from util import log_r class FML32: GPARM32_0 = 0x0a000c80 SEND_PARMS_NUM32 = 0x0a000ce4 RECP_PARMS
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txt 9_19data.txt

please input the message length to n: 384 please input the con_len to K: 3 please input the largest retrans num: 5 你选择的编码深度所对应的穿孔矩阵及其它信息如下: M G1 G2 the punc_table the coding rate: 2 5 7 1
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py jsd0262.py

#!/usr/bin/env python # -*- coding: utf-8 -*- #Jensen-Shannon Divergence import codecs, re, math f1=codecs.open(r"./T0262_utf8.txt", "r", "utf8") f2=codecs.open(r"./T0265_utf8.txt", "r", "utf
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m l3n2.m

function [A1_min, A2_min, A3_min] = L3n2(s_size, level, model, ini_point, x00, sf, Np, Nd, dm, ws, wp, outname) % Optimize the coding gain subject to the error of h1 is less than dh1 % with second-o
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m l3n.m

function [A1_min, A2_min, A3_min] = L3n(s_size, level, model, ini_point, x00, sf, Np, Nd, dm, ws, wp, outname) % optimize the coding gain subject to the error of h1 is less than dh1 % with second-orde
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py a8.py

# -*- coding: cp936 -*- #第八章----数字0~9的奇妙变换 #《c趣味编程》58-68题 #21:48 2006-11-4 from collections import deque from math import log10 def permute(seq, index): seqc = seq[:] seqn = [seqc.pop()]