代码搜索:Bit

找到约 10,000 项符合「Bit」的源代码

代码结果 10,000
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c bit_xor.c

#include void main () { printf("0 ^ 0 is %d\n", 0 ^ 0); printf("0 ^ 1 is %d\n", 0 ^ 1); printf("1 ^ 1 is %d\n", 1 ^ 1); printf("1 ^ 2 is %d\n", 1 ^ 2); printf("15 ^
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c bit_inv.c

#include void main () { int value = 0xFF; printf("The inverse of %X is %X\n", value, ~value); }
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bit emif_com.bit

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java sum_of_bit.java

/** * @(#)Sum_of_Bit.java * * * @author * @version 1.00 2009/3/1 */ /** *本程序的功能是求得一个0到1000范围的整数的各位上的数字和 *基本思路是用模(%)和除(/)的运算来实现 */ import javax.swing.JOptionPane; public class Su
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class sum_of_bit.class

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m bit_gen.m

%gives the complex fade coefficients %output power is approximately unity %inputs:max_doppler_freq (Hz); sample_freq (Hz); num_samples function [bit_vec] = bit_gen(num_bits, seed) rand(
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m encode_bit.m

function [output, state] = encode_bit(g, input, state) [n,k] = size(g); m = k-1; for i=1:n output(i) = g(i,1)*input; for j = 2:k output(i) = xor(output(i),g(i,j)*state(j-1)); end
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m encode_bit.m

function [output, state] = encode_bit(g, input, state) % Copyright 1996 Matthew C. Valenti % MPRG lab, Virginia Tech % for academic use only % This function takes as an input a single bit to be encod
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c bit_xor.c

#include void main () { printf("0 ^ 0 is %d\n", 0 ^ 0); printf("0 ^ 1 is %d\n", 0 ^ 1); printf("1 ^ 1 is %d\n", 1 ^ 1); printf("1 ^ 2 is %d\n", 1 ^ 2); printf("15 ^
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c bit_inv.c

#include void main () { int value = 0xFF; printf("The inverse of %X is %X\n", value, ~value); }