代码搜索：ANSY
找到约 56 项符合「ANSY」的源代码
代码结果 56
www.eeworm.com/read/115402/15014755
txt ansy 接口.txt
如何将AutoCAD图形导入到ANSYS进行处理
AutoCAD 模型输入 Ansys
1. 对于三维实体(3d Object)
AutoCAD:
File --> Export... --> 保存类型选 ACIS(*.sat) --> 输入文件名 --> 选实体 (选3d object)
Ansys:
File --> Import --> SAT... 输入即可
www.eeworm.com/read/361039/10068114
v ansy_fifo_top.v
/*************************************************
* 模块名：asyn_fifo_top
* 时 间：2007-05-14
* 设计者：张波涛
* 说 明：FIFO的顶层模块
*************************************************/
// `include "times
www.eeworm.com/read/217040/14981517
pas bcuint.pas
PROCEDURE bcuint(y,y1,y2,y12: gl4array; x1l,x1u,x2l,x2u,x1,x2: real;
VAR ansy,ansy1,ansy2: real);
(* Programs using procedure BCUINT must define the types
TYPE
gl4array = ARRAY [1..4] O
www.eeworm.com/read/431812/8652527
cpp pku2059.cpp
#include
#define size 51
typedef struct Point
{
int x, y;
} Point;
Point p[size];
int S, H;
int check(int x, int y)
{
int min, tmp;
int i;
min = 100000;
tmp = x * x;
www.eeworm.com/read/362573/9990601
cpp zoj1511.cpp
#include
#include
using namespace std;
struct trienode {
trienode* ch[26];
int key;
trienode(int x=-1):key(x) {
for(int i=0;i
www.eeworm.com/read/211952/15169685
cpp p1574.cpp
#include
#include
#define Limit 100000
int Ansx [Limit + 100] , Ansy [Limit + 100] , Ansz [Limit + 100];
bool prime ( int a , int b )
{
return b == 0 ? a ==
www.eeworm.com/read/211952/15169778
pas p2438.pas
PROGRAM p2448;
VAR
part,p,n,m :Integer;
max,ansx,ansy :Integer;
data :array[1..60,1..60]of Integer;
map
www.eeworm.com/read/291235/8432599
cpp xbcuint.cpp
#include
#include
#include "nr.h"
using namespace std;
// Driver for routine bcuint
int main(void)
{
const DP xx_d[4]={0.0,2.0,2.0,0.0};
const DP yy_d[
www.eeworm.com/read/431812/8652435
cpp pku2142.cpp
#include
#define ONLINE
#ifndef ONLINE
#include
#endif
int Mod(int a, int b)
{
if (b == 0)
{
return a;
}
return a % b;
}
int ABS(int x)
{
return x > 0 ?
www.eeworm.com/read/431812/8653361
cpp pku1723.cpp
#include
#include
#define size 11000
using namespace std;
int x[size], y[size];
int N;
int ABS(int x)
{
return x > 0 ? x : -x;
}
int CalcX(int X)
{
int ans = 0;