代码搜索:ADC按键设计
找到约 10,000 项符合「ADC按键设计」的源代码
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www.eeworm.com/read/477459/6736095
txt adc0809.txt
程序设计内容
(1). 进行A/D转换时,采用查询EOC的标志信号来检测A/D转换是否完毕,若完毕则把数据通过P0端口读入,经过数据处理之后在数码管上显示。
(2). 进行A/D转换之前,要启动转换的方法:
ABC=110选择第三通道
ST=0,ST=1,ST=0产生启动转换的正脉冲信号 .
汇编源程序
CH EQU 30H
DPCNT EQ ...
www.eeworm.com/read/476712/6748684
h adc_ts.h
/*
* FILE: adc_ts.h
* ADC和触摸屏的测试函数接口
*/
#ifndef __ADC_TS_H__
#define __ADC_TS_H__
/*
* 测试ADC
* 通过A/D转换,测量可变电阻器的电压值
*/
void Test_Adc(void);
/*
* 测试触摸屏,打印触点坐标
*/
www.eeworm.com/read/476712/6748694
lds adc_ts.lds
SECTIONS {
. = 0x00000000;
.init : AT(0){ head.o init.o nand.o}
. = 0x30000000;
.text : AT(4096) { *(.text) }
.rodata ALIGN(4) : AT((LOADADDR(.text)+SIZEOF(.text)+3)&~(0x03)) {*(.r
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c adc_ts.c
/*
* FILE: adc_ts.c
* ADC和触摸屏的测试函数
*/
#include
#include "adc_ts.h"
#include "s3c24xx.h"
#include "serial.h"
// ADCCON寄存器
#define PRESCALE_DIS (0
www.eeworm.com/read/476812/6751111
src test-adc.src
[Files]
usart.c
lcd.c
delay.c
main.c
[Headers]
delay.h
lcd.h
usart.h
[Documents]
www.eeworm.com/read/476812/6751113
dbg test-adc.dbg
IMAGECRAFT DEBUG FORMAT
VERSION 1.1
CPU AVR
DIR F:\radio\第十一篇\test-adc\
FILE usart.c
FUNC putchar AC fV
BLOCK 7 AC
DEFREG coutput 16 c
LINE 7 AC
LINE 8 AC
LINE 8 AC
LINE 9 B0
BLOCKEND 0 B2
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hex test-adc.hex
:080000000C9435000C9432024F
:040038000C94CB0158
:14005400000000302E30560041443020564F4C544147453A93
:010068000097
:14006A00CFE5D4E0CDBFDEBFC051D0400AEA08830024E5E761
:14007E00F0E010E0ED37F10711F0
www.eeworm.com/read/476812/6751115
mak test-adc.mak
CC = iccavr
CFLAGS = -IC:\icc\include\ -e -DATMEGA -DATMega16 -l -g -Mavr_enhanced
ASFLAGS = $(CFLAGS) -Wa-g
LFLAGS = -LC:\icc\lib\ -g -ucrtatmega.o -bfunc_lit:0x54.0x4000 -dram_end:0x45f -bda
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mp test-adc.mp
NOTE: AVR Code addresses are word addresses
All other addresses (including ones in FLASH) are byte addresses
Area Addr Size Decimal Bytes (Attributes)
----------
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prj test-adc.prj
[Compiler Options]
Edit1=C:\icc\include\
Edit2=C:\icc\lib\
Edit8=
CheckBox1=0
CheckBox2=1
Edit3=
Edit4=
Edit11=16
Edit13=
ComboBox1=0
Edit9=16384
Edit10=1024
ComboBox2=9
RadioGroup1=0
E