代码搜索：3526
找到约 64 项符合「3526」的源代码
代码结果 64
www.eeworm.com/read/418779/10900550
txt 3526.txt
Rule:
--
Sid:
3526
--
Summary:
This event is generated when an attempt is made to exploit a vulnerability
associated with the Oracle XML Database (XDB) FTP UNLOCK command.
--
Impact:
A successful a
www.eeworm.com/read/7227/112078
asm 3526.asm
;**** A P P L I C A T I O N N O T E A V R 1 0 0 ************************
;*
;* 标题: 测试指令功能原理
;* 版本: 1.0
;*最后更新日期: 2000.08.08
;*
;* 支援 E-mail: gzsl@sl.com.cn
;*
;* 描述
;* 用AVR Studio调试软件
www.eeworm.com/read/14182/309871
htm 3526.htm
www.eeworm.com/read/15647/520547
htm 3526.htm
www.eeworm.com/read/473927/6822613
txt 3526.txt
Rule:
--
Sid:
3526
--
Summary:
This event is generated when an attempt is made to exploit a vulnerability
associated with the Oracle XML Database (XDB) FTP UNLOCK command.
--
Impact:
A successful a
www.eeworm.com/read/426535/9014586
m ex3526.m
%例35-26：用Jacobi迭代法求解下列线性方程组。
A=[4 -1 1;-1 4.25 2.75;1 2.75 3.5]; %系数矩阵A
b=[13,-9,6]'; %矩阵B
[x,n]=jacobi(A,b,[0,0,0]',1.0e-6)
www.eeworm.com/read/319431/13451805
m ex3526.m
%例35-26：用Jacobi迭代法求解下列线性方程组。
A=[4 -1 1;-1 4.25 2.75;1 2.75 3.5]; %系数矩阵A
b=[13,-9,6]'; %矩阵B
[x,n]=jacobi(A,b,[0,0,0]',1.0e-6)
www.eeworm.com/read/319404/13452269
m ex3526.m
%例35-26：用Jacobi迭代法求解下列线性方程组。
A=[4 -1 1;-1 4.25 2.75;1 2.75 3.5]; %系数矩阵A
b=[13,-9,6]'; %矩阵B
[x,n]=jacobi(A,b,[0,0,0]',1.0e-6)
www.eeworm.com/read/345494/11812421
m ex3526.m
%例35-26：用Jacobi迭代法求解下列线性方程组。
A=[4 -1 1;-1 4.25 2.75;1 2.75 3.5]; %系数矩阵A
b=[13,-9,6]'; %矩阵B
[x,n]=jacobi(A,b,[0,0,0]',1.0e-6)