代码搜索：10 是什么？
找到约 10,000 项符合「10 是什么？」的源代码
代码结果 10,000
www.eeworm.com/read/287194/8710557
c 10rkt10.c
#include "stdio.h"
#include "10rkt1.c"
main()
{ int i,j;
void rkt1f(double,double [],int,double []);
double t,h,y[3],z[3][11];
y[0]=-1.0; y[1]=0.0; y[2]=1.0;
t=0.0; h
www.eeworm.com/read/287194/8710622
c 10elr10.c
#include "stdio.h"
#include "10elr1.c"
main()
{ int i,j;
void elr1f(double,double [],int,double []);
double y[3],z[3][11],t,h,x;
y[0]=-1.0; y[1]=0.0; y[2]=1.0;
t=0.0;
www.eeworm.com/read/430670/8734125
tif 表10-10.tif
www.eeworm.com/read/429840/8786001
m examp10_10.m
net=newff([0,1; -1,5],[8,1],{'tansig','logsig'});
net=newff([0,1; -1,5],[4 6 1],{'purelin','tansig','logsig'});
net.trainParam.epochs=300; net.trainFcn='trainlm'
www.eeworm.com/read/385645/8794991
c alg10-10.c
/* alg10-10.c 归并排序，包括算法10.12～10.14 */
#include
typedef int InfoType; /* 定义其它数据项的类型 */
#include"c9-7.h"
#include"c10-1.h"
void Merge(RedType SR[],RedType TR[],int i,int m,int n)
www.eeworm.com/read/428838/8836400
asm 10-10-2.asm
;10-10-2.ASM 传送端
$MOD51
ORG 0000H
SJMP START
ORG 0023H
SJMP SERIAL
;
ORG 0030H
START: MOV R2,#100
ACALL DELAY
ACALL DELAY
MOV TMOD,#21H
MOV TH1,#0FDH
SETB TR1
MOV SCON,#50H
www.eeworm.com/read/428838/8836445
asm 10-10-1.asm
;10-10-1.ASM 接收端
$MOD51
CNT DATA 030H
;
ORG 0000H
SJMP START
ORG 0023H
SJMP SERIAL
;
ORG 0030H
START: MOV CNT,#0
MOV TMOD,#21H
MOV TH1,#0FDH
SETB TR1
MOV SCON,#50H
SETB ES
S
www.eeworm.com/read/384841/8839215
c alg10-10.c
/* alg10-10.c 归并排序 */
#include
typedef int InfoType; /* 定义其它数据项的类型 */
#include"c9.h"
#include"c10-1.h"
void Merge(RedType SR[],RedType TR[],int i,int m,int n)
{ /* 将有序的SR[i..m]
www.eeworm.com/read/284781/8899315
m 例程10-10.m
% 采用补零的扩展模式（参见dwtmode函数）
% 装载一维尺度信号
load leleccum;
s = leleccum(1:3920);
% 使用db1在第3层进行分解
[c,l] = wavedec(s,3,'db1');
subplot(4,1,1);plot(s);
title('原始信号');
% 从小波分解结构[c,l]中提取1、2及3层的细节系数
[cd1
www.eeworm.com/read/427573/8935277
c 10rkt10.c
#include "stdio.h"
#include "10rkt1.c"
main()
{ int i,j;
void rkt1f(double,double [],int,double []);
double t,h,y[3],z[3][11];
y[0]=-1.0; y[1]=0.0; y[2]=1.0;
t=0.0; h