代码搜索:10 是什么?

找到约 10,000 项符合「10 是什么?」的源代码

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htm ch10_10.htm

Recipe 10.9. Returning More Than One Array or Hash (Perl Cookbook)
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m example10_10.m

I1= imread('circles.tif'); imshow(I1); I2 = bwmorph(I1,'skel',Inf); imshow(I2) I3= bwmorph(I1,'thin',Inf); imshow(I3)
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gif 10tyt10.gif

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cpp pgm10_10.cpp

// // This file contains the C++ code from Program 10.10 of // "Data Structures and Algorithms // with Object-Oriented Design Patterns in C++" // by Bruno R. Preiss. // // Copyright (c) 199
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cpp ch10_10.cpp

//*********************** //** ch10_10.cpp ** //*********************** #include struct Person { char name[20]; unsigned long id; float salary; }; void GetPerson
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c 10rkt10.c

#include "stdio.h" #include "10rkt1.c" main() { int i,j; void rkt1f(double,double [],int,double []); double t,h,y[3],z[3][11]; y[0]=-1.0; y[1]=0.0; y[2]=1.0; t=0.0; h
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c 10elr10.c

#include "stdio.h" #include "10elr1.c" main() { int i,j; void elr1f(double,double [],int,double []); double y[3],z[3][11],t,h,x; y[0]=-1.0; y[1]=0.0; y[2]=1.0; t=0.0;
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c alg10-10.c

/* alg10-10.c 归并排序 */ #include typedef int InfoType; /* 定义其它数据项的类型 */ #include"c9.h" #include"c10-1.h" void Merge(RedType SR[],RedType TR[],int i,int m,int n) { /* 将有序的SR[i..m]
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c 10rkt10.c

#include "stdio.h" #include "10rkt1.c" main() { int i,j; void rkt1f(double,double [],int,double []); double t,h,y[3],z[3][11]; y[0]=-1.0; y[1]=0.0; y[2]=1.0; t=0.0; h
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c 10elr10.c

#include "stdio.h" #include "10elr1.c" main() { int i,j; void elr1f(double,double [],int,double []); double y[3],z[3][11],t,h,x; y[0]=-1.0; y[1]=0.0; y[2]=1.0; t=0.0;