代码搜索：预置数
找到约 10,000 项符合「预置数」的源代码
代码结果 10,000
www.eeworm.com/read/16645/681821
txt 猜数游戏.txt
#include
#include
#include
void main( )
{
char input[10],s,b;
int i,a,j=0;
printf("\t\t猜数游戏\n");
printf("系统随机产生一个1-100之间的整数，猜测这个整数！\n");
printf("A:模式
www.eeworm.com/read/41490/920748
vi 计算峰数.vi
www.eeworm.com/read/41682/921067
vi 计算峰数.vi
www.eeworm.com/read/327496/3455287
c 阿姆斯特朗数.c
#include
main()
{
int i,t,k,a[3];
printf("There are following Armstrong number smaller than 1000: \n");
for(i=152;i=10;t++)
{
a[t]=(i%k)/(k/1
www.eeworm.com/read/474440/6809437
c 阿姆斯特朗数.c
#include
main()
{
int i,t,k,a[3];
printf("There are following Armstrong number smaller than 1000: \n");
for(i=152;i=10;t++)
{
a[t]=(i%k)/(k/1
www.eeworm.com/read/394038/8250758
ppt 特殊的数.ppt
www.eeworm.com/read/270091/11048885
cpp 删数问题.cpp
#include
using namespace std;
const int Limit_Size = 100;
char num[ Limit_Size ];
int k, n;
void init( )
{
cin >> num >> k;
n = strlen( num );
}
void del(
www.eeworm.com/read/411858/11224044
dsn 摸数转换.dsn
www.eeworm.com/read/411858/11224066
pwi 摸数转换.pwi
www.eeworm.com/read/248263/12587221
txt 十数和.txt
10 rem calculate add of ten integers
20 input X
30 let n = n + 1
40 let t = t + X
50 if n == 10 goto 70
60 goto 20
70 print t , N
80 end