代码搜索：音频数字
找到约 10,000 项符合「音频数字」的源代码
代码结果 10,000
www.eeworm.com/read/251029/4425195
c example5.c
#include
void main()
{
int num, count=0;
printf("\n请输入数字：\n");
scanf("%d",&num);
do
{
num = num / 10;/* 提取该数的位数 */
count ++;
}while (num >0); /* do...while 循环结束 */
print
www.eeworm.com/read/251029/4425267
c table.c
# include
void main()
{
int a;
printf("\n请输入一个数字：");
scanf("%d",&a);
printf ("\n %d * 1 = %d \t %d * 2 = %d", a, a*1, a, a*2);
printf ("\n %d * 3 = %d \t %d * 4 = %d", a, a
www.eeworm.com/read/347831/3162260
java isortnumber.java
package book.oo.sort;
/**
* 定义数字排序的接口
*/
public interface ISortNumber {
/**
* 对整型数组按升序排序
* @param intArray 待排序的整型数组
* @return 按升序排序后的数组
*/
public int[] sortASC(int[] intArray);
www.eeworm.com/read/347831/3162337
java password.java
package book.string;
import java.security.MessageDigest;
/**
* 对密码进行加密和验证的程序
*/
public class Password {
/** 十六进制下数字到字符的映射数组 */
private final static String[] hexDigits = { "0", "1", "2
www.eeworm.com/read/345154/3201871
java isortnumber.java
package book.oo.sort;
/**
* 定义数字排序的接口
*/
public interface ISortNumber {
/**
* 对整型数组按升序排序
* @param intArray 待排序的整型数组
* @return 按升序排序后的数组
*/
public int[] sortASC(int[] intArray);
www.eeworm.com/read/345154/3201941
java password.java
package book.string;
import java.security.MessageDigest;
/**
* 对密码进行加密和验证的程序
*/
public class Password {
/** 十六进制下数字到字符的映射数组 */
private final static String[] hexDigits = { "0", "1", "2
www.eeworm.com/read/335724/3356547
java isortnumber.java
package book.oo.sort;
/**
* 定义数字排序的接口
*/
public interface ISortNumber {
/**
* 对整型数组按升序排序
* @param intArray 待排序的整型数组
* @return 按升序排序后的数组
*/
public int[] sortASC(int[] intArray);
www.eeworm.com/read/335724/3356624
java password.java
package book.string;
import java.security.MessageDigest;
/**
* 对密码进行加密和验证的程序
*/
public class Password {
/** 十六进制下数字到字符的映射数组 */
private final static String[] hexDigits = { "0", "1", "2