代码搜索：零序保护
找到约 10,000 项符合「零序保护」的源代码
代码结果 10,000
www.eeworm.com/read/352745/10519922
asv shiyu.asv
%时域分析
%利用卷积求零状态响应
t=0:0.01:1
h=exp(-1*t) %generates h(k)
e=1*t %generates x(k)
r=0.01*conv(e,h) %caculate r(k)=T*h(k)*e(k)
plot(t,r(1:101),'+')
axis([0,1,0,0.4])
%冲激响应
%step
clc
clear
www.eeworm.com/read/160253/10548863
m example2_11_1.m
x = [1 2 3] %原始信号
l = 2; %一维延拓长度
xextzpd1 = wextend('1','zpd',x,l) %一维零填充
xextzpd2 = wextend('1D','zpd',x,l,'b')
xextsym = wextend('1D','sym',x,l) % 一维对称延拓
xextper = wextend('1D','per',x,l)
www.eeworm.com/read/160251/10549642
m 例程13-5.m
% 当前的延拓模式是补零
% 产生高斯白噪声
init = 2055415866; randn('seed',init);
x = randn(1,1000);
% 寻找各个阈值选择规则的阈值
% 使用SURE的自适应阈值
thr1 = thselect(x,'rigrsure')
% 固定形式阈值
thr2 = thselect(x,'sqtwolog')
% 启发式阈值
www.eeworm.com/read/423304/10572358
c bo5-2.c
/* bo5-2.c 三元组稀疏矩阵的基本操作,包括算法5.1(9个) */
Status CreateSMatrix(TSMatrix *M)
{ /* 创建稀疏矩阵M */
int i,m,n;
ElemType e;
Status k;
printf("请输入矩阵的行数,列数,非零元素数：");
scanf("%d,%d,%d",&(*M).
www.eeworm.com/read/422872/10605275
m meshetc.m
clear
clc
[x,y,z] =peaks;
subplot(2,3,1);
meshz(x,y,z); %曲面加上围裙,即给出曲面和零平面
axis([-inf inf -inf inf -inf inf]);
subplot(2,3,2);
waterfall(x,y,z); %在x方向产生水流效果
axis([-inf inf -inf inf -inf inf])
www.eeworm.com/read/274718/10857106
cpp 6_17.cpp
#include
using namespace std;
int NumZeros(int Array[][4][3], int n1, int n2, int n3) //统计三维数组中零数值个数
{ int count = 0;
for (int i = 0; i < n1; i++)
for (int j = 0; j < n2; j++)
www.eeworm.com/read/272198/10965968
m meshetc.m
clear
clc
[x,y,z] =peaks;
subplot(2,3,1);
meshz(x,y,z); %曲面加上围裙,即给出曲面和零平面
axis([-inf inf -inf inf -inf inf]);
subplot(2,3,2);
waterfall(x,y,z); %在x方向产生水流效果
axis([-inf inf -inf inf -inf inf])
www.eeworm.com/read/417241/10998877
m caltime.m
function PVal=caltime(P,T,M,PNumber,MNumber,WPNumber)
% T=[4 6 7 0 ;8 7 9 1; 1 2 4 0];
% M=[1 2 3 0; 3 2 1 3; 2 1 3 0];
% P=[31 21 32 11 12 13 33 22 23 24];
%
% PNumber=3; %零件 个数 3
% MNumb
www.eeworm.com/read/271252/11001744
m caltime.m
function PVal=caltime(P,T,M,PNumber,MNumber,WPNumber)
% T=[4 6 7 0 ;8 7 9 1; 1 2 4 0];
% M=[1 2 3 0; 3 2 1 3; 2 1 3 0];
% P=[31 21 32 11 12 13 33 22 23 24];
%
% PNumber=3; %零件 个数 3
% MNumb
www.eeworm.com/read/469630/6972350
m buling.m
N=70;%N为补零的点数
t=-1:0.1:1;
x=[0 0.1 0.2 0.3 0.4 0.5 0.6 0.7 0.8 0.9 1 0.9 0.8 0.7 0.6 0.5 0.4 0.3 0.2 0.1 0];
stem(t,x);
X=fft(x,length(t));
figure,stem(fftshift(abs(X)));
x=[x zeros(1,N)];
t=-1