代码搜索：链表实现
找到约 10,000 项符合「链表实现」的源代码
代码结果 10,000
www.eeworm.com/read/393381/8291154
txt 单链表的操作.txt
//2． 单链表
#include
#define elemtype int
using namespace std;
class link
{ public:
elemtype data;
link *next;};
link *hcreat()
{ link *s,*p;
elemtype i;
p=new li
www.eeworm.com/read/247693/12627307
txt 单链表的反转.txt
有一单链表n1->n2->...n(x-1)->nx,请问如何在不使用辅助节点的情况下实现该链表的反转呢? 反转后变成nx->n(x-1)->...n2->n1 .
（随机测试，最大最至20000，都能有正确的结果）
代码如下：
#include
#include
#define S
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exe 单链表的删除.exe
www.eeworm.com/read/235777/14053412
c 单链表的查找.c
/* 单链表的查找：带头结点的单链表中，判断有无结点的值等于x，有则返回当前指针，没有返回空*/
#include "Stdio.h"
#include "Conio.h"
#define flag 0
typedef int datatype;
//结点定义
typedef struct node
{
datatype data;
struct nod
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exe 单链表的查找.exe
www.eeworm.com/read/203179/15364438
h 模板链表_02.h
#ifndef EXAMPLE9_02_H
#define EXAMPLE9_02_H
#include
#include
using namespace std;
template
class ListNode //结点类
{
public:
ListNode(){}
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txt 单链表~1.txt
www.eeworm.com/read/107030/15614544
c 双链表正排序.c
#include
#include
#include
struct list{
int data;
struct list *next;
struct list *pre;
};
typedef struct list node;
typedef node *link;
link fr
www.eeworm.com/read/107030/15614546
c 建立链表1.c
/* 链表建立程序 */
#include"stdio.h"
#include
#define NULL 0
#define LEN sizeof(struct student)
struct student
{long num;
int score;
struct student *next;
};
int n; /*全局变量n*/
str
www.eeworm.com/read/107030/15614549
c 单链表倒序.c
#include
struct fsb
{
int data;
int flag;
struct fsb * next;
};
main()
{
struct fsb *p,*head,*sta,*end;
int i,cishu,j;
end=(struct fsb *)malloc(sizeof(struct fsb))