代码搜索:递归回溯

找到约 2,805 项符合「递归回溯」的源代码

代码结果 2,805
www.eeworm.com/read/473760/1396897

txt factorial.txt

{递归调用测试} {功能:对于输入n,输出n的阶乘} program sd var integer s; integer t; procedure factor(integer n;var integer m); var integer w; begin if n=0 then m:=1 else factor(n-1,w); m:=n*w fi en
www.eeworm.com/read/471368/1431487

java gcd_recursion.java

//【习3.24】 将辗转相除法求两个整数的最大公因数gcd(a,b)用递归方法实现。 public class GCD_recursion { public static int gcd(int a,int b) //返回a,b的最大公因数 { if (b==0) return a;
www.eeworm.com/read/195829/5107189

txt 6_8.txt

int PostTreeDepth(BiTree bt) /* 后序遍历求二叉树的高度递归算法 */ { int hl,hr,max; if(bt!=NULL) { hl=PostTreeDepth(bt->LChild); /* 求左子树的深度 */ hr=PostTreeDepth(bt->RChild); /* 求右子树的深度 */ max=hl>hr
www.eeworm.com/read/191242/5166661

bas alex3.bas

' 八皇后问题的递归解法 DIM A(8), S, MAX S = 0: MAX = 0 GOTO MAIN SEARCH: A(S) = 0 WHILE A(S) < 8 OK = 1 X = 0 WHILE (X < S) IF (A(X) = A(S)) THEN OK = 0' 哈哈还没有ABS靠下面两句实现
www.eeworm.com/read/191242/5166670

bas alex3.bas

' 八皇后问题的递归解法 DIM A(8), S, MAX S = 0: MAX = 0 GOTO MAIN SEARCH: A(S) = 0 WHILE A(S) < 8 OK = 1 X = 0 WHILE (X < S) IF (A(X) = A(S)) THEN OK = 0' 哈哈还没有ABS靠下面两句实现
www.eeworm.com/read/191242/5166680

bas alex3.bas

' 八皇后问题的递归解法 DIM A(8), S, MAX S = 0: MAX = 0 GOTO MAIN SEARCH: A(S) = 0 WHILE A(S) < 8 OK = 1 X = 0 WHILE (X < S) IF (A(X) = A(S)) THEN OK = 0' 哈哈还没有ABS靠下面两句实现
www.eeworm.com/read/191242/5166689

bas alex3.bas

' 八皇后问题的递归解法 DIM A(8), S, MAX S = 0: MAX = 0 GOTO MAIN SEARCH: A(S) = 0 WHILE A(S) < 8 OK = 1 X = 0 WHILE (X < S) IF (A(X) = A(S)) THEN OK = 0' 哈哈还没有ABS靠下面两句实现
www.eeworm.com/read/164351/5490022

txt factorial.txt

{递归调用测试} {功能:对于输入n,输出n的阶乘} program sd var integer s; integer t; procedure factor(integer n;var integer m); var integer w; begin if n=0 then m:=1 else factor(n-1,w); m:=n*w fi en
www.eeworm.com/read/303129/3815379

txt 6_8.txt

int PostTreeDepth(BiTree bt) /* 后序遍历求二叉树的高度递归算法 */ { int hl,hr,max; if(bt!=NULL) { hl=PostTreeDepth(bt->LChild); /* 求左子树的深度 */ hr=PostTreeDepth(bt->RChild); /* 求右子树的深度 */ max=hl>hr
www.eeworm.com/read/475726/6776427

cpp algo0706.cpp

void BFSTraverse(Graph G, Status (*Visit)(int v )) {// 算法7.6 // 按广度优先非递归遍历图G。使用辅助队列Q和访问标志数组visited。 QElemType v,w; queue Q; QElemType u; for (v=0; v