代码搜索:递归回溯
找到约 2,805 项符合「递归回溯」的源代码
代码结果 2,805
www.eeworm.com/read/37150/899502
c recursion.c
/* 递归法将整数转换成字符 */
# include
void convert(int n)
{
int i;
if((i=n/10) != 0)
convert(i);
putchar(n%10+'0');
}
void main()
{
int number;
printf("输入整数:");
scanf("%d", &n
www.eeworm.com/read/35567/1059332
c recursion.c
/* 递归法将整数转换成字符 */
# include
void convert(int n)
{
int i;
if((i=n/10) != 0)
convert(i);
putchar(n%10+'0');
}
void main()
{
int number;
printf("输入整数:");
scanf("%d", &n
www.eeworm.com/read/237765/4620861
c recursion.c
/* 递归法将整数转换成字符 */
# include
void convert(int n)
{
int i;
if((i=n/10) != 0)
convert(i);
putchar(n%10+'0');
}
void main()
{
int number;
printf("输入整数:");
scanf("%d", &n
www.eeworm.com/read/339658/3296303
c recursion.c
/* 递归法将整数转换成字符 */
# include
void convert(int n)
{
int i;
if((i=n/10) != 0)
convert(i);
putchar(n%10+'0');
}
void main()
{
int number;
printf("输入整数:");
scanf("%d", &n
www.eeworm.com/read/304661/3786394
java fibonacci.java
public class Fibonacci{
private int fib(int n){//利用方法的递归调用
if(n==0) return 0;
if(n==1) return 1;
if(n>1) return fib(n-2)+fib(n-1);
return 0;
}
public static void main(St
www.eeworm.com/read/288165/4009437
c recursion.c
/* 递归法将整数转换成字符 */
# include
void convert(int n)
{
int i;
if((i=n/10) != 0)
convert(i);
putchar(n%10+'0');
}
void main()
{
int number;
printf("输入整数:");
scanf("%d", &n
www.eeworm.com/read/285305/4054214
java fibonacci.java
public class Fibonacci{
private int fib(int n){//利用方法的递归调用
if(n==0) return 0;
if(n==1) return 1;
if(n>1) return fib(n-2)+fib(n-1);
return 0;
}
public static void main(St
www.eeworm.com/read/274119/4188933
c recursion.c
/* 递归法将整数转换成字符 */
# include
void convert(int n)
{
int i;
if((i=n/10) != 0)
convert(i);
putchar(n%10+'0');
}
void main()
{
int number;
printf("输入整数:");
scanf("%d", &n
www.eeworm.com/read/195211/8168423
c recursion.c
/* 递归法将整数转换成字符 */
# include
void convert(int n)
{
int i;
if((i=n/10) != 0)
convert(i);
putchar(n%10+'0');
}
void main()
{
int number;
printf("输入整数:");
scanf("%d", &n
www.eeworm.com/read/248079/12602904
c recursion.c
/* 递归法将整数转换成字符 */
# include
void convert(int n)
{
int i;
if((i=n/10) != 0)
convert(i);
putchar(n%10+'0');
}
void main()
{
int number;
printf("输入整数:");
scanf("%d", &n