代码搜索：递归回溯
找到约 2,805 项符合「递归回溯」的源代码
代码结果 2,805
www.eeworm.com/read/134037/14011906
c 二进制数.c
/*递归法求二进制数*/
#include
void printb(int x,int n);
void main()
{
int x;
printf("input number:");
scanf("%d",&x);
printf("number of decimal form: %d\n",x);
www.eeworm.com/read/204479/15337777
c tree_preorder_rec.c
/* 树的后根周游的递归算法*/
#include
#include
#define MAXNUM 20
#define null -1
/* typedef int DataType; */
struct ParTreeNode {
/*DataType info; 结点中的元素 */
int paren
www.eeworm.com/read/201037/15417870
cpp tower.cpp
#include
void Towers(int n, char fromPeg, char auxPeg, char toPeg)
// 把n个盘子从fromPeg借助auxPeg移至toPeg
{
if(n==1) //递归出口
{
cout
www.eeworm.com/read/111298/15515018
cpp tower.cpp
#include
void Towers(int n, char fromPeg, char auxPeg, char toPeg)
// 把n个盘子从fromPeg借助auxPeg移至toPeg
{
if(n==1) //递归出口
{
cout
www.eeworm.com/read/110336/15536316
java app6_12.java
// app6_12, 简单的递归method
public class app6_12
{
public static void main(String args[])
{
System.out.println("1*2*..*4 = "+fac(4));
}
public static int fac(int n) /
www.eeworm.com/read/110094/15541945
java app6_12.java
// app6_12, 简单的递归method
public class app6_12
{
public static void main(String args[])
{
System.out.println("1*2*..*4 = "+fac(4));
}
public static int fac(int n) /
www.eeworm.com/read/109219/15561751
c 二进制数.c
/*递归法求二进制数*/
#include
void printb(int x,int n);
void main()
{
int x;
printf("input number:");
scanf("%d",&x);
printf("number of decimal form: %d\n",x);
www.eeworm.com/read/101253/15839274
c 二进制数.c
/*递归法求二进制数*/
#include
void printb(int x,int n);
void main()
{
int x;
printf("input number:");
scanf("%d",&x);
printf("number of decimal form: %d\n",x);
www.eeworm.com/read/100753/15865222
c 二进制数.c
/*递归法求二进制数*/
#include
void printb(int x,int n);
void main()
{
int x;
printf("input number:");
scanf("%d",&x);
printf("number of decimal form: %d\n",x);
www.eeworm.com/read/371950/9529349
cpp main.cpp
/*******************************************************************************
20. (Ｎ皇后) 在国际象棋的棋盘上放置Ｎ个皇后，使其不能互相攻击，即任意
两个皇后不能处在棋盘的同一行，同一列，同一斜线上，试问共有多少种摆法？
利用回溯法求解N皇后问题
**********************